Given a linked list, rotate the list to the right by k places, where k is non-negative.
Example 1:
Input: 1->2->3->4->5->NULL, k = 2 Output: 4->5->1->2->3->NULL Explanation: rotate 1 steps to the right: 5->1->2->3->4->NULL rotate 2 steps to the right: 4->5->1->2->3->NULL
Example 2:
Input: 0->1->2->NULL, k = 4 Output:2->0->1->NULL
Explanation: rotate 1 steps to the right: 2->0->1->NULL rotate 2 steps to the right: 1->2->0->NULL rotate 3 steps to the right:0->1->2->NULL
rotate 4 steps to the right:2->0->1->NULL
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* rotateRight(ListNode* head, int k) { if (!head) return NULL; ListNode* newN; ListNode* tail; newN = tail = head; int len = 1; while (tail->next) { tail = tail->next; len++; } tail->next = head; if (k %= len) { for (int i = 0; i < len - k; ++i) { tail = tail->next; } } newN = tail->next; tail->next = NULL; return newN; } };