Given an integer n, return the number of trailing zeroes in n!.
Example 1:
Input: 3
Output: 0
Explanation: 3! = 6, no trailing zero.
Example 2:
Input: 5
Output: 1
Explanation: 5! = 120, one trailing zero.
Note: Your solution should be in logarithmic time complexity.
class Solution(object):
def trailingZeroes(self, n):
"""
:type n: int
:rtype: int
"""
a = 0
while(n):
n = int(n / 5)
a = a + n
return a