Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
class Solution { public: int lengthOfLastWord(const char *s) { int res=0; if(NULL==s)return res; int len=strlen(s); while(s[len-1]==' ')len--; for(int i=len-1;i>=0;i--) { if(s[i]!=' ') res++; else break; } return res; } };