动态创建菜单使得程序灵活性大大增加，本文根据读取xml文件中的配置菜单项来动态创建菜单，代码如下：
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using WinformMenu.Helper;
using System.Xml;
namespace WinformMenu
{
public partial class FrmAddMenu : Form
{
public FrmAddMenu()
{
InitializeComponent();
}
private void FrmAddMenu_Load(object sender, EventArgs e)
{
MenuStrip menuS = new MenuStrip();
menuS.Parent = this;
string xmlFileName = @"F:\c#工程\WinformMenu\WinformMenu\XML\菜单.xml";
createMenu(xmlFileName, menuS);
}
public void createMenu(string xmlFileName, MenuStrip menuS)
{
//1：根据XmlElement创建菜单
//XmlNode node = xmlHelper.GetXmlNode(xmlFileName, "//MangeTvMenu");
//foreach (XmlNode xml in node.ChildNodes)
//{
// ToolStripMenuItem mainMenu=new ToolStripMenuItem();
// mainMenu.Text = xml.Attributes["descript"].Value;
// menuS.Items.Add(mainMenu);
// if (xml.HasChildNodes)
// {
// CreateSubMenuByNode(xml, mainMenu);
// }
//}
//2：根据XmlNode创建菜单
XmlElement xml = xmlHelper.GetXmlElement(xmlFileName);
foreach (XmlElement xel in xml.ChildNodes)
{
ToolStripMenuItem mainMenu = new ToolStripMenuItem();
mainMenu.Text = xel.Attributes["descript"].Value;
menuS.Items.Add(mainMenu);
if (xml.HasChildNodes)
{
CreateSubMenuByElement(xel, mainMenu);
}
}
}
/// <summary>
/// 根据node节点递归创建菜单
/// </summary>
/// <param name="xNode"></param>
/// <param name="menuItem"></param>
public void CreateSubMenuByNode(XmlNode xNode, ToolStripMenuItem menuItem)
{
foreach (XmlNode xml in xNode.ChildNodes)
{
ToolStripMenuItem subMenu = new ToolStripMenuItem();
if (xml.ChildNodes.Count > 1)
{
subMenu.Text = xml.Attributes["descript"].Value;
menuItem.DropDown.Items.Add(subMenu);
CreateSubMenuByNode(xml, subMenu);
}
else
{
subMenu.Text = xml.InnerText;
menuItem.DropDown.Items.Add(subMenu);
}
}
}
/// <summary>
/// 根据元素节点递归创建菜单
/// </summary>
/// <param name="xml"></param>
/// <param name="menuItem"></param>
public void CreateSubMenuByElement(XmlElement xml, ToolStripMenuItem menuItem)
{
foreach (XmlElement xel in xml.ChildNodes)
{
ToolStripMenuItem subMenu = new ToolStripMenuItem();
if (xel.ChildNodes.Count>1)
{
subMenu.Text = xel.Attributes["descript"].Value;
menuItem.DropDown.Items.Add(subMenu);
CreateSubMenuByElement(xel, subMenu);
}
else
{
subMenu.Text = xel.InnerText;
menuItem.DropDown.Items.Add(subMenu);
}
}
}
///////////////////////////////////////////////////
}
}
xml文件格式如下：
<?xml version="1.0" encoding="utf-8" ?>
<MangeTvMenu descript="管理">
<Add descript="添加">
<Employee>员工</Employee>
<Deptment>部门</Deptment>
</Add>
<EmployeeInfo descript="员工信息">
<BaseInfo>个人基本信息</BaseInfo>
<StudyInfo>学历信息</StudyInfo>
<MarryInfo>婚姻信息</MarryInfo>
</EmployeeInfo>
<DeptmentInfo descript="部门信息">
<dept1>部门1</dept1>
<dept2>部门2</dept2>
</DeptmentInfo>
<MoneyManage descript="工资管理">
<BaseMoney>基本工资</BaseMoney>
<OtherMoney>绩效工资</OtherMoney>
</MoneyManage>
<Apply descript="申请">
<AddWork>加班</AddWork>
<ApplyWeek>请假</ApplyWeek>
<AddMoney>加薪</AddMoney>
<Another>其他</Another>
</Apply>
</MangeTvMenu>
效果如下图所示：
xmlHelper为自己写的一个操作xml的类，由于比较简单在此就不贴代码了。
发现如果将xel.ChildNodes.Count>1(也就是上面红色字体代码)换成xel.HasChildNodes程序就会报错，目前正在思考此问题，欢迎广大朋友指点。
