Turn the corner

Turn the corner

Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 654 Accepted Submission(s): 291

Problem Description Mr. West bought a new car! So he is travelling around the city. One day he comes to a vertical corner. The street he is currently in has a width x, the street he wants to turn to has a width y. The car has a length l and a width d. Can Mr. West go across the corner?

Input Every line has four real numbers, x, y, l and w. Proceed to the end of file.

Output If he can go across the corner, print "yes". Print "no" otherwise.

Sample Input 10 6 13.5 4 10 6 14.5 4

Sample Output yes no

Source 2008 Asia Harbin Regional Contest Online

Recommend gaojie

/*
x和y值和题目相反，搞了了好几遍
*/
#include<bits/stdc++.h>
#define exp 1e-9
#define pi acos(-1)
using namespace std;
/*
小车不靠墙壁段的直线方程 
*/
double dis(double Q,double l,double d,double x)
{
    double b=d/cos(Q)+l*sin(Q);
    return (b-x)/tan(Q);
}
int main()
{
    //freopen("C:\\Users\\acer\\Desktop\\in.txt","r",stdin);
    double x,y,l,d;
    while(scanf("%lf%lf%lf%lf",&x,&y,&l,&d)!=EOF)
    {
        double left=0,right=pi/2,mid,midmid;
        //cout<<right<<endl;
        while(right-left>exp)
        {
            mid=left+(right-left)/3;
            midmid=right-(right-left)/3;
            //假设求解最大极值.
            if(dis(mid,l,d,x)>=dis(midmid,l,d,x))
                right=midmid;
            else 
                left=mid;
        }
        //cout<<"mid="<<mid<<endl;
        //cout<<(int)dis(mid,l,d,x)<<endl;
        if(dis(mid,l,d,x)<y)
            puts("yes");
        else
            puts("no");
    }
    return 0;
}

 

我每天都在努力,只是想证明我是认真的活着.