A1036. Boys vs Girls

题目难度，简单；注意事项，初始化时，最低分和最高分不要搞反

 

 

 

 

基本思路

• 构造Person结构体，属性，姓名，性别，编号，分数
• 初始化Girl与Boy属性，在遍历中记录Girl最高分和Boy最低分
• 检查是否缺失男性或者女性，按照题目要求输出对应格式

#include <bits/stdc++.h>

using namespace std;

struct Person{
    int score;
    string name, id, sex;
}Girl, Boy, temp;

void init(){
    Girl.score = 0;
    Girl.sex = 'F';
    Boy.score = 100;
    Boy.sex = 'M';
}

int main(int argc, char* argv[]) {
    init();
    int n, score;
    cin >> n;
    string name, id, sex;
    bool flag_M, flag_F;
    flag_M = flag_F = false;
    for(int i = 0; i < n; i++){    
        cin >> name >> sex >> id >> score;
        if(sex == "M"){
            flag_M = true;
            if(score < Boy.score){
                Boy.id = id;
                Boy.name = name;
                Boy.score = score;
            }    
        }else if(sex == "F"){
            flag_F = true;
            if(score > Girl.score){
                Girl.id = id;
                Girl.name = name;
                Girl.score = score;
            }    
        }        
    } 
    bool flag = false;
    // 不存在女生 
    if(flag_F == false){
        flag = true;
        cout << "Absent" << endl;
    }else{
        cout << Girl.name << ' ' << Girl.id << endl;        
    }
    // 不存在男生 
    if(flag_M == false){
        flag = true;
        cout << "Absent" << endl;
    }else{
        cout << Boy.name << ' ' << Boy.id << endl;
    }
    if(flag){
        cout << "NA" << endl;
    }else{
        cout << (Boy.score < Girl.score ? Girl.score - Boy.score : Boy.score - Girl.score) << endl;
    }
    return 0;
}

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