前言
题目
<?php /** * 给定url,获取文件后缀 * @param string $url * @return string */ function getUrlPostfix ($url) { $url_arr = explode('.', $url); $postfix = $url_arr[count($url_arr) - 1]; $substr = substr($postfix, 0, 3); return $substr; } $url = "http://www.feiyan.info/test.php?c=class&m=method"; $str = getUrlPostfix($url); echo $str . "\n";
<?php /** * 每隔3个字符,用逗号进行分隔 * @param string $str * @return string */ function splitStrWithComma ($str) { $arr = array(); $len = strlen($str); for ($i = $len - 1; $i >= 0;) { $new_str = ""; for ($j = $i; $j > $i - 3 && $j >= 0; $j --) { $new_str .= $str[$j]; } $arr[] = $new_str; $i = $j; } $string = implode(',', $arr); // 翻转字符串自己实现 // $string = strrev($string); for ($i = 0, $j = strlen($string) - 1; $i <= $j; $i ++, $j --) { $tmp = $string[$i]; $string[$i] = $string[$j]; $string[$j] = $tmp; } return $string; } $str = "1234567890"; $new_str = splitStrWithComma($str); echo $new_str . "\n";
(3)写一个php函数算出两个文件的相对路径。例如$a="/a/b/c/d/e.php"; $b="/a/b/12/34/c.php",B相对于A的相对路径是什么?
<?php /** * 求$b相对于$a的相对路径 * @param string $a * @param string $b * @return string */ function getRelativePath ($a, $b) { $patha = explode('/', $a); $pathb = explode('/', $b); $counta = count($patha) - 1; $countb = count($pathb) - 1; $path = "../"; if ($countb > $counta) { while ($countb > $counta) { $path .= "../"; $countb --; } } // 寻找第一个公共结点 for ($i = $countb - 1; $i >= 0;) { if ($patha[$i] != $pathb[$i]) { $path .= "../"; $i --; } else { // 判断是否为真正的第一个公共结点,防止出现子目录重名情况 for ($j = $i - 1, $flag = 1; $j >= 0; $j --) { if ($patha[$j] == $pathb[$j]) { continue; } else { $flag = 0; break; } } if ($flag) break; else $i ++; } } for ($i += 1; $i <= $counta; $i ++) { $path .= $patha[$i] . "/"; } return $path; } $a = "/a/c/d/e.php"; $b = "/a/c.php"; $path = getRelativePath($a, $b); echo $path;
(4)计算两个日期之间的天数
<?php /** * 求两个日期之间相差的天数(针对1970年1月1日之后,求之前可以采用泰勒公式) * @param string $day1 * @param string $day2 * @return number */ function diffBetweenTwoDays ($day1, $day2) { $second1 = strtotime($day1); $second2 = strtotime($day2); if ($second1 < $second2) { $tmp = $second2; $second2 = $second1; $second1 = $tmp; } return ($second1 - $second2) / 86400; } $day1 = "2013-07-27"; $day2 = "2013-08-04"; $diff = diffBetweenTwoDays($day1, $day2); echo $diff."\n";