Description

Farmer John made a profit last year! He would like to invest it well but wonders how much money he will make. He knows the interest rate R (an integer between 0 and 20) that is compounded annually at his bank. He has an integer amount of money M in the range 100..1,000,000. He knows how many years Y (range: 0..400) he intends to invest the money in the bank. Help him learn how much money he will have in the future by compounding the interest for each year he saves. Print an integer answer without rounding. Answers for the test data are guaranteed to fit into a signed 32 bit integer. 看了样例输入输出就知道怎么回事了..........

Input

* Line 1: Three space-separated integers: R, M, and Y

Output

* Line 1: A single integer that is the number of dollars FJ will have after Y years.

Sample Input

5 5000 4

INPUT DETAILS:

5% annual interest, 5000 money, 4 years

Sample Output

6077

OUTPUT DETAILS:

Year 1: 1.05 * 5000 = 5250
Year 2: 1.05 * 5250 = 5512.5
Year 3: 1.05 * 5512.50 = 5788.125
Year 4: 1.05 * 5788.125 = 6077.53125
The integer part of 6077.53125 is 6077.

 

一大波水题正在接近……

真是没什么好说的，求m*(1+r/100)^y

我有特殊的缩代码技巧

#include<cstdio>
double r,m;
int y;
int main()
{
	scanf("%lf%lf%d",&r,&m,&y);
	while (y--)m*=(1+r/100);
	printf("%d",(int)m);
}