3343: 教主的魔法
Time Limit: 10 Sec Memory Limit: 256 MBSubmit: 1444 Solved: 653
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Description
Input
Output
Sample Input
1 2 3 4 5
A 1 5 4
M 3 5 1
A 1 5 4
Sample Output
3
HINT
Source
第一次写分块题。。。
就是每一块的个数为根号n
修改:
对于一整块,直接打add标记
头尾俩块不完整的进行暴力修改重构
查询
每一块内排序,在第i块内二分查找大等于C-add[i]的数字
头尾俩块暴力查询
#include<iostream> #include<cstdio> #include<cmath> #include<algorithm> using namespace std; int n,m,cnt,a[1000010],b[1000010],pos[1000010],block,ADD[1010]; void Set(int x){ int l=(x-1)*block+1,r=min(n,x*block); for(int i=l;i<=r;i++)b[i]=a[i]; sort(b+l,b+r+1); } void Grow(int x,int y,int z){ if(pos[x]==pos[y])for(int i=x;i<=y;i++)a[i]+=z; else { for(int i=x;i<=pos[x]*block;i++)a[i]+=z; for(int i=(pos[y]-1)*block+1;i<=y;i++)a[i]+=z; } Set(pos[x]);Set(pos[y]); for(int i=pos[x]+1;i<pos[y];i++)ADD[i]+=z; } int coco(int x,int v){ int l=(x-1)*block+1,r=min(n,x*block);int last=r; while(l<=r){ int mid=(l+r)>>1; if(b[mid]<v)l=mid+1; else r=mid-1; } return last-l+1; } int Ask(int x,int y,int z){ int ans=0; if(pos[x]==pos[y]){ for(int i=x;i<=y;i++)if(a[i]+ADD[pos[i]]>=z)ans++; } else{ for(int i=x;i<=pos[x]*block;i++)if(a[i]+ADD[pos[i]]>=z)ans++; for(int i=(pos[y]-1)*block+1;i<=y;i++)if(a[i]+ADD[pos[i]]>=z)ans++; } for(int i=pos[x]+1;i<pos[y];i++)ans+=coco(i,z-ADD[i]); return ans; } int main(){ scanf("%d%d",&n,&m); block=(int)(sqrt(n)); for(int i=1;i<=n;i++){ scanf("%d",&a[i]); pos[i]=(i-1)/block+1; b[i]=a[i]; } if(n%block)cnt=n/block+1; else cnt=n/block; for(int i=1;i<=cnt;i++)Set(i); char ch[5];int x,y,z; for(int i=1;i<=m;i++){ scanf("%s%d%d%d",ch,&x,&y,&z); if(ch[0]=='M')Grow(x,y,z); if(ch[0]=='A')printf("%d\n",Ask(x,y,z)); } }