<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">
<bean id="personDao" class="cn.itcast.dao.impl.PersonDaoBean"></bean>
<bean id="personService" class="cn.itcast.service.impl.PersonServiceBean">
<property name="sets">
<set>
<value>第一个</value>
<value>第二个</value>
<value>第三个</value>
</set>
</property>
<property name="lists">
<list>
<value>第一个list元素</value>
<value>第二个list元素</value>
<value>第三个list元素</value>
</list>
</property>
<property name="properties">
<props>
<prop key="key1">value1</prop>
<prop key="key2">value2</prop>
<prop key="key3">value3</prop>
</props>
</property>
<property name="maps">
<map>
<entry key="key-1" value="value-1"></entry>
<entry key="key-2" value="value-2"></entry>
<entry key="key-3" value="value-3"></entry>
</map>
</property>
</bean>
</beans>
---------------------------------------------------------
public class PersonServiceBean implements PersonService {
private Set<String> sets=new HashSet<String>();
private List<String> lists=new ArrayList<String>();
private Properties properties=new Properties();
private Map<String,String> maps=new HashMap<String,String>();
public Set<String> getSets() {
return sets;
}
public void setSets(Set<String> sets) {
this.sets = sets;
}
public List<String> getLists() {
return lists;
}
public void setLists(List<String> lists) {
this.lists = lists;
}
public Properties getProperties() {
return properties;
}
public void setProperties(Properties properties) {
this.properties = properties;
}
public Map<String, String> getMaps() {
return maps;
}
public void setMaps(Map<String, String> maps) {
this.maps = maps;
}
}
-----------------------------------------------------------------------------
public interface PersonService {
public Set<String> getSets();
public List<String> getLists();
public Properties getProperties();
public Map<String, String> getMaps();
}
-------------------------------------------------------
public class SpringTest {
@Test
public void instanceSpring() {
AbstractApplicationContext ctx = new ClassPathXmlApplicationContext("beans.xml");
PersonService personService = (PersonService)ctx.getBean("personService");//Scope为prototype时调用getBean()时实例化bean
for(String value:personService.getSets()){
System.out.println(value);
}
System.out.println("=====list=====");
for(String value:personService.getLists()){
System.out.println(value);
}
System.out.println("=====properties=====");
for(Object key:personService.getProperties().keySet()){
System.out.println(key+"="+personService.getProperties().getProperty((String)key));
}
System.out.println("=====map=====");
for(Object key:personService.getMaps().keySet()){
System.out.println(key+"="+personService.getMaps().get((String)key));
}
ctx.close();// 关闭Spring容器
}
}
集合类型的装配
转载本文章为转载内容,我们尊重原作者对文章享有的著作权。如有内容错误或侵权问题,欢迎原作者联系我们进行内容更正或删除文章。
提问和评论都可以,用心的回复会被更多人看到
评论
发布评论
相关文章
-
集合类型的装配
知识点:【第一:设置集合属性public class OrderServiceBean { private Set sets = n
集合类型的装配 java System xml -
spring 装配集合
1:创建pojo,属性包含集合,集合元素为基本类型 2:装配bean 3:创建pojo,属性包含集合,集合元素为对象类型 装配类: 4:装备bean
spring xml java 对象类型 基本类型 -
宋体集合Spring装配集合的四个方法及实现
近期一直在查找宋体集合之类的问题,下午正好有机会和大家讨论一下.四种配装集合在这我我直接用utilschema集合,用util签标需只要把util的约
spring xml java 键值 map集合