/* Copyright (C) 1999 Lucent Technologies */
/* From 'Programming Pearls' by Jon Bentley */

/* bitsort.c -- bitmap sort from Column 1
* Sort distinct integers in the range [0..N-1]
*/

#include <stdio.h>

#define BITSPERWORD 32
#define SHIFT 5
#define MASK 0x1F // MASK = 31
#define N 1000000
int a[1 + N/BITSPERWORD];
//i >> SHIFT -> i >> 5 -> i/32 -> 数字i所对应的数组的index
//i & MASK -> i & 31 -> i % 32 -> 对应数组元素的bit位
//a[i >> SHIFT] -> 指的是i所在的位所在的数组位置
//1<<(i & MASK)
void set(int i) { a[i>>SHIFT] |= (1<<(i & MASK)); }
void clr(int i) { a[i>>SHIFT] &= ~(1<<(i & MASK)); }
int test(int i){ return a[i>>SHIFT] & (1<<(i & MASK)); }

int main()
{ int i;
for (i = 0; i < N; i++)
clr(i);
/* Replace above 2 lines with below 3 for word-parallel init
int top = 1 + N/BITSPERWORD;
for (i = 0; i < top; i++)
a[i] = 0;
*/
while (scanf("%d", &i) != EOF)
set(i);
for (i = 0; i < N; i++)
if (test(i))
printf("%d\n", i);
}