题目传送门

 1 /*
 2     DFS：油田问题，一道经典的DFS求连通块。当初的难题，现在看上去不过如此啊
 3 */
 4 /************************************************
 5 Author        :Running_Time
 6 Created Time  :2015-8-4 10:11:11
 7 File Name     :HDOJ_1241.cpp
 8 ************************************************/
 9 
10 #include <cstdio>
11 #include <algorithm>
12 #include <iostream>
13 #include <sstream>
14 #include <cstring>
15 #include <cmath>
16 #include <string>
17 #include <vector>
18 #include <queue>
19 #include <deque>
20 #include <stack>
21 #include <list>
22 #include <map>
23 #include <set>
24 #include <bitset>
25 #include <cstdlib>
26 #include <ctime>
27 using namespace std;
28 
29 #define lson l, mid, rt << 1
30 #define rson mid + 1, r, rt << 1 | 1
31 typedef long long ll;
32 const int MAXN = 1e2 + 10;
33 const int INF = 0x3f3f3f3f;
34 const int MOD = 1e9 + 7;
35 char maze[MAXN][MAXN];
36 bool vis[MAXN][MAXN];
37 int dx[8] = {-1, 1, 0, 0, -1, -1, 1, 1};
38 int dy[8] = {0, 0, -1, 1, -1, 1, -1, 1};
39 int n, m;
40 
41 bool judge(int x, int y)    {
42     if (x < 1 || x > n || y < 1 || y > m || vis[x][y] || maze[x][y] != '@') return false;
43     return true;
44 }
45 
46 void DFS(int x, int y)  {
47     for (int i=0; i<8; ++i) {
48         int tx = x + dx[i], ty = y + dy[i];
49         if (!judge (tx, ty))    continue;
50         vis[tx][ty] = true; DFS (tx, ty);
51     }
52 }
53 
54 int main(void)    {     //HDU 1241 Oil Deposits
55     while (scanf ("%d%d", &n, &m) == 2) {
56         if (m == 0) break;
57         for (int i=1; i<=n; ++i)    {
58             scanf ("%s", maze[i] + 1);
59         }
60         memset (vis, false, sizeof (vis));
61         int ans = 0;
62         for (int i=1; i<=n; ++i)    {
63             for (int j=1; j<=m; ++j)    {
64                 if (maze[i][j] == '@' && !vis[i][j]) {
65                     ans++;  vis[i][j] = true;   DFS (i, j);
66                 }
67             }
68         }
69         printf ("%d\n", ans);
70     }
71 
72     return 0;
73 }

 

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