We use Perl scripts to check if condition.

##code(t1) is as belows:    my @results=(93,4,0);  my @param_array = (            [ "50", "<", "stat1", ],            [ "1", "<", "stat2", ],            [ "3", "<", "stat3", ],           );     for ($i=0;$i<@results;$i++) {    print (" ".$results[$i]." ".$param_array[$i][1]." ".$param_array[$i][0]." ");  if  ( $results[$i] + 0 < $param_array[i][0] + 0 ) {  print "  beend";  } else { print "  end111";  }   }

The result is strange. When 95<50, ​​if​​​ condition is not true, and it prints ​​end111​​. I think the statement is right.

But when 4 < 1, ​​if​​​ condition is not true, it also prints ​​beend​​. I think the the statement is wrong.

Why does this happen?

###result is as below perl t1    93 < 50   end111       4 < 1   beend      0 < 3   beend


fix:

0

You should add ​​use warnings;​​ to your code, and you should see warning messages like:

Unquoted string "i" may clash with future reserved word Argument "i" isn't numeric in array element

You need to change ​​i​​​ to ​​$i​​. Change:

if ( $results[$i] + 0 < $param_array[i][0] + 0 ) {

to:

if ( $results[$i] + 0 < $param_array[$i][0] + 0 ) {

This produces the following output, which I assume is what you want (although you didn't explicitly show your expected output:

 93 < 50   end111  4 < 1   beend  0 < 3   beend