// Problem: B. Sonya and Exhibition
// Contest: Codeforces - Codeforces Round #495 (Div. 2)
// URL: https://codeforces.com/problemset/problem/1004/B
// Memory Limit: 256 MB
// Time Limit: 1000 ms
// 2022-03-09 11:07:59
//
// Powered by CP Editor (https://cpeditor.org)
#include<bits/stdc++.h>
using namespace std;
#define rep(i,l,r) for(int i=(l);i<=(r);i++)
#define per(i,l,r) for(int i=(l);i>=(r);i--)
#define ll long long
#define mset(s,t) memset(s,t,sizeof(t))
#define mcpy(s,t) memcpy(s,t,sizeof(t))
#define fi first
#define se second
#define pb push_back
#define all(x) (x).begin(),(x).end()
#define SZ(x) ((int)(x).size())
#define mp make_pair
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> Vll;
typedef vector<pair<int, int> > vpii;
typedef vector<pair<ll, ll> > vpll;
const ll mod = 1e9 + 7;
//const ll mod = 998244353;
const double pi = acos(-1.0);
inline ll qmi (ll a, ll b) {
ll ans = 1;
while (b) {
if (b & 1) ans = ans * a%mod;
a = a * a %mod;
b >>= 1;
}
return ans;
}
inline int read () {
int x = 0, f = 0;
char ch = getchar();
while (!isdigit(ch)) f |= (ch=='-'),ch= getchar();
while (isdigit(ch)) x = x * 10 + ch - '0', ch = getchar();
return f?-x:x;
}
template<typename T> void print(T x) {
if (x < 0) putchar('-'), x = -x;
if (x >= 10) print(x/10);
putchar(x % 10 + '0');
}
inline ll sub (ll a, ll b) {
return ((a - b ) %mod + mod) %mod;
}
inline ll add (ll a, ll b) {
return (a + b) %mod;
}
inline ll inv (ll a) {
return qmi(a, mod - 2);
}
void solve() {
int n, m;
cin >> n >> m;
vector<pii> a(m + 1);
vector<int> d (n + 1, 0);
for (int i = 1; i <= n ;i ++) {
cin >> a[i].fi >> a[i].se;
}
sort(all(a));
for (int i = 1; i <= n; i ++)
d[i] = i%2;
for (int i = 1; i<= n; i++)cout <<d[i];
puts("");
}
int main () {
// ios::sync_with_stdio(0),cin.tie(0), cout.tie(0);
int t;
t =1;
//cin >> t;
while (t --) solve();
return 0;
}
题意:给你一些区间,要求每个区间的漂亮值和最大。 分散01,就可以让我数组的值最大。这样就可以避免某个区间内全部为1或者0;