需求
很简单的知识点,做一下小结。
最近写代码需要做一下切片的操作,比如给定这样一个切片:
lst1 = [1,2,3,4,5,6,7,8,9,10,11,12,13]
将这个切片里面的元素按照每4个为一组,每一组组成单独的切片,然后再组合到外层的切片中,结果像这样:
[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13]]
python的写法
# -*- coding:utf-8 -*-
lst1 = [1,2,3,4,5,6,7,8,9,10,11,12,13]
lst2 = ["w","wg","wa","jj","aa","ff","gg","hh","asd","ww","ee","gg","nn","mm"]
print(len(lst1)) # 13
print(len(lst2)) # 14
### 超限切片
ret_lst1 = list()
ret_lst2 = list()
# 根据lst1构建新的列表
for i in range(0,len(lst1),4):
curr_lst = lst1[i:i+4]
ret_lst1.append(curr_lst)
# 根据lst2构建新的列表
for i in range(0,len(lst2),4):
curr_lst = lst2[i:i+4]
ret_lst2.append(curr_lst)
### 注意结果最后一个列表不足的话不会报错
print(ret_lst1) # [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13]]
print(ret_lst2) # [['w', 'wg', 'wa', 'jj'], ['aa', 'ff', 'gg', 'hh'], ['asd', 'ww', 'ee', 'gg'], ['nn', 'mm']]
Go的写法
错误的写法
package t9
import (
"fmt"
"testing"
)
func TestOutRange(t *testing.T) {
lst1 := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13}
lst2 := []string{"w", "wg", "wa", "jj", "aa", "ff", "gg", "hh", "asd", "ww", "ee", "gg", "nn", "mm"}
fmt.Println(len(lst1)) // 13
fmt.Println(len(lst2)) // 14
// 结果
var retLst1 [][]int
var retLst2 [][]string
// 超限切片
for i := 0; i < len(lst1); i += 4 {
currLst := lst1[i : i+4]
retLst1 = append(retLst1, currLst)
}
for i := 0; i < len(lst2); i += 4 {
currLst := lst2[i : i+4]
retLst2 = append(retLst2, currLst)
}
}
这样写会上报一个错误:
--- FAIL: TestOutRange (0.00s)
panic: runtime error: slice bounds out of range [:16] with capacity 13 [recovered]
panic: runtime error: slice bounds out of range [:16] with capacity 13
错误的原因是,我们每次获取currLst的时候,是按照 lst[i i+4] 这样直接切片的,但是,如果i+4大于列表lst的长度的话,会上报越界错误!
正确的写法 ***
既然i+4可能会超出lst的长度越界,那我们在切片的时候判断一下二者的大小即可:
package t9
import (
"fmt"
"testing"
)
// 返回两个int最小的那个
func minInt(a, b int) int {
if a < b {
return a
}
return b
}
func TestOutRange(t *testing.T) {
lst1 := []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13}
lst2 := []string{"w", "wg", "wa", "jj", "aa", "ff", "gg", "hh", "asd", "ww", "ee", "gg", "nn", "mm"}
fmt.Println(len(lst1)) // 13
fmt.Println(len(lst2)) // 14
// 结果
var retLst1 [][]int
var retLst2 [][]string
// 切片
for i := 0; i < len(lst1); i += 4 {
// 保证不越界
currLst := lst1[i:minInt(i+4, len(lst1))]
retLst1 = append(retLst1, currLst)
}
for i := 0; i < len(lst2); i += 4 {
// 保证不越界
currLst := lst2[i:minInt(i+4, len(lst2))]
retLst2 = append(retLst2, currLst)
}
// 注意结果有填充的默认值
fmt.Println(retLst1) // [[1 2 3 4] [5 6 7 8] [9 10 11 12] [13]]
fmt.Println(retLst2) // [[w wg wa jj] [aa ff gg hh] [asd ww ee gg] [nn mm]]
}
~~~