题目描述

输入两棵二叉树A,B,判断B是不是A的子结构。(ps:我们约定空树不是任意一个树的子结构)

​https://www.nowcoder.com/practice/6e196c44c7004d15b1610b9afca8bd88?tpId=13&tqId=11170&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking​

题解:

子结构不是子树(leetcode 572)

class Solution {
public:
bool isSubtree(TreeNode* pRoot1, TreeNode* pRoot2) {
if (pRoot2 == NULL) {
return true;
}
if (pRoot1 == NULL) {
return false;
}
if (pRoot1->val == pRoot2->val) {
return isSubtree(pRoot1->left, pRoot2->left) && isSubtree(pRoot1->right, pRoot2->right);
}
return false;
}
bool HasSubtree(TreeNode* pRoot1, TreeNode* pRoot2)
{
if (pRoot1 == NULL || pRoot2 == NULL) {
return false;
}
return isSubtree(pRoot1, pRoot2) || HasSubtree(pRoot1->left, pRoot2) || HasSubtree(pRoot1->right, pRoot2);
}
};