Given an array ​​nums​​ of n integers and an integer ​​target​​​, find three integers in ​​nums​​​ such that the sum is closest to ​​target​​. Return the sum of the three integers. You may assume that each input would have exactly one solution.

Example:

Given array nums = [-1, 2, 1, -4], and target = 1.

The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

题解:

class Solution {
public:
int threeSumClosest(vector<int>& nums, int target) {
int n = nums.size();
int ans = nums[0] + nums[1] + nums[2];
sort(nums.begin(), nums.end());
for (int i = 0; i < n - 2; i++) {
int j = i + 1, k = n - 1;
while (j < k) {
int sum = nums[i] + nums[j] + nums[k];
if (sum == target) {
return sum;
}
else if (sum > target) {
if (sum - target < abs(ans - target)) {
ans = sum;
}
k--;
}
else {
if (target - sum < abs(ans - target)) {
ans = sum;
}
j++;
}
}
while (nums[i] == nums[i + 1]) {
i++;
}
}
return ans;
}
};