LeetCode-1310. XOR Queries of a Subarray
原创
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Given the array arr
of positive integers and the array queries
where queries[i] = [Li, Ri]
, for each query i
compute the XOR of elements from Li
to Ri
(that is, arr[Li] xor arr[Li+1] xor ... xor arr[Ri]
). Return an array containing the result for the given queries
.
Example 1:
Input: arr = [1,3,4,8], queries = [[0,1],[1,2],[0,3],[3,3]]
Output: [2,7,14,8]
Explanation:
The binary representation of the elements in the array are:
1 = 0001
3 = 0011
4 = 0100
8 = 1000
The XOR values for queries are:
[0,1] = 1 xor 3 = 2
[1,2] = 3 xor 4 = 7
[0,3] = 1 xor 3 xor 4 xor 8 = 14
[3,3] = 8
Example 2:
Input: arr = [4,8,2,10], queries = [[2,3],[1,3],[0,0],[0,3]]
Output: [8,0,4,4]
Constraints:
-
1 <= arr.length <= 3 * 10^4
-
1 <= arr[i] <= 10^9
-
1 <= queries.length <= 3 * 10^4
-
queries[i].length == 2
-
0 <= queries[i][0] <= queries[i][1] < arr.length
题解:
class Solution {
public:
vector<int> xorQueries(vector<int>& arr, vector<vector<int>>& queries) {
int n = arr.size();
vector<int> pre(n + 1, 0);
vector<int> res;
for (int i = 0; i < n; i++) {
pre[i + 1] = arr[i] ^ pre[i];
}
for (int i = 0; i < queries.size(); i++) {
int tmp = pre[queries[i][0]] ^ pre[queries[i][1] + 1];
res.push_back(tmp);
}
return res;
}
};