方法一：通过sympy的方法进行计算
from sympy import Symbol,solve,pprint
x = Symbol('x')
y = Symbol('y')
n = Symbol('n')
m = Symbol('m')
expr1 = x + y - n
expr2 =2*x+4*y- m
solution = solve((expr1,expr2),(x,y),dict=True)
chicken = solution[0][x].subs({n:35,m:94})
rabbits = solution[0][y].subs({n:35,m:94})
print(f'There are {chicken} chicken.')
print(f'There are {rabbits} rabbits.')结果如下：
There are 23 chicken.
There are 12 rabbits.方法二：通过解析式编写函数求解
假设有只鸡，
只兔子，我们可以列出以下方程组：
得到的解为：
据此，我们可以写出以下函数进行该问题的求解：
def chicken_and_rabbits(nheads,mlegs):
rabnum = mlegs/2 - nheads
chinum = 2*nheads - mlegs/2
return chinum,rabnum
chicken = int(chicken_and_rabbits(35,94)[0])
rabbits = int(chicken_and_rabbits(35,94)[1])
print(f'There are {chicken} chicken.')
print(f'There are {rabbits} rabbits.')最后的结果如下：
There are 23 chicken.
There are 12 rabbits.
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