前言：不知道有没有人和我一样，学习python编程的时候有个想法，模似中奖程序，预测中奖号码。废话不多说，直接实操。

一、红球1-32 蓝球1-15

二、中奖规则

一等奖：6个红色球号码+1个蓝色球号码全中。（6+1）
red == 6 and blue ==1
二等奖：6个红色球号码全中。（6+0）
red == 6
三等奖：5个红色球号码+1个蓝色球号码。（5+1）
red == 5 and blue == 1
四等奖：5个红色球号码或者4个红色球号码+1个蓝色球号码
red + blue == 5
五等奖：4个红色球号码或者3个红色球号码+1个蓝色球号码
red + blue == 4 
六等奖：2个红色球号码+1个蓝色球号码或者1个红色球号码+1个蓝色球号码或者只有1个蓝
(red == 2 and blue == 1) or (red ==1 and blue ==1) or blue == 1

三、random模块使用

nums = []
for i in range(6):
    while True:
        num = randint(1, 32)
        if num not in nums:
            nums.append(num)
            break
blue = randint(1, 15)
nums = sorted(nums)
nums.append(blue)

四、1、随机生成6个红球，随机生成1个蓝球。

      2、根据规则判断中几等奖


from random import randint

def create_num():
    nums = []
    for i in range(6):
        while True:
            num = randint(1, 32)
            if num not in nums:
                nums.append(num)
                break
    blue = randint(1, 15)
    nums = sorted(nums)
    nums.append(blue)
    return nums

def pan_duan(nums, buy_num):
    red = 0
    blue = 0
    for i in buy_num[:-1]:  # 判断中了多少个
        if i in nums[:-1]:
            red += 1
    if nums[-1] == buy_num[-1]:  # 判断蓝球有没有中
        blue +=1

    if red == 6 and blue ==1:
        return 1
    elif red == 6:
        return 2
    elif red == 5 and blue == 1:
        return 3
    elif red + blue == 5:
        return 4
    elif red + blue == 4:
        return 5
    elif (red == 2 and blue == 1) or (red ==1 and blue ==1) or blue == 1:
        return 6
    else:
        return 0

nums = create_num()
buy_num = [3, 7, 12, 22, 23, 25, 29]
print(f"您中了：{pan_duan(nums, buy_num)}  等奖" )


sum_count =0
for i in range(10000):
    nums = create_num()
    # print(nums)
    count = pan_duan(nums, buy_num)
    if count != 0:
        print(f"第{i}次中{count}等奖")
        sum_count +=1
print(f"共中奖：{sum_count}次")


python生成中奖号码工具_python编程