一、字典输出
import json
dict1 = {'School':'zhoubei','Name': '张三', 'Age': 7, 'Class': '第一班'}
print dict1['School']
print json.dumps(dict1).decode('unicode-escape')
二、if /while 循环
-------输入三个数字，是否能组成三角形，并判断是什么三角形--------
n1 = int(raw_input('请输入第一个整数数字：'))
n2 = int(raw_input('请输入第二个整数数字：'))
n3 = int(raw_input('请输入第三个整数数字：'))
if n1 + n2> n3 and n2 + n3> n1 and n1 + n3> n2: #两边之和大于第三边
if n1 == n2 and n2 == n3:
print ('这是个等边三角形')
elif n1 == n2 or n2 == n3 or n1 == n3:
print ('这是个等腰三角形')
elif n1**2+n2**2 == n3**2 or n2**2 + n3**2 == n1**2 or n1**2 + n3**2 == n2**2: #符合勾股定理为直角三角形
print ('这是个直角三角形')
else:
print ('这是个普通的三角形')
else:
print ('无法组成三角形：')
-----------------与电脑猜拳-------------------
import random
import json
dict_c = {1:'石头',2:'剪刀',3:'布'}
dict_u = {'石头':1,'剪刀':2,'布':3}
user = raw_input('请输入：(只能是石头/剪刀/布)')
user1 = dict_u[user]
computer = random.randint(1,3)
c = dict_c[computer]
if user != '石头' and user != '剪刀' and user != '布':
print('你又调皮了，只能输入石头/剪刀/布')
else:
print('电脑出：')
print json.dumps(c).decode('unicode-escape')
print("输赢结果：")
if user == c:
print('平手')
elif user1 == 1 and computer == 3:
print('SB，你输啦')
elif user1 == 2 and computer == 1:
print('SB，你输啦')
elif user1 == 3 and computer == 2:
print('SB，你输啦')
else:
print('你走狗屎运了')
-----------------输出100以内的素数-------------------
n=2
while(n<100):
i = 2 #i从2开始
while(i<=10):
if n%i == 0:
break
i+=1
if (i>n/i):
print n
n+=1
三、for 循环
#公鸡3元/只，母鸡5元/只，小鸡每元3只
-----------------100元买100只鸡-------------------
for x in range(33): # 100元内，公鸡数不能超过33只
for y in range(20): # 同理，母鸡不能超过20只
for z in range(100): # 同理，小鸡不会超过100只
if 3*x+5*y+(1.0/3)*z ==100 and x+y+z==100:
print x,y,z
--------------输出1-9,0-----------------
list1 = range(10)
list1.append(list1.pop(0))
print list1
#一对兔子每月生一对兔子，刚出生的兔子两个月后才能生育
--------------21个月兔子数量-----------------
num1 = 2
num2 = 2
sum = 0
for i in range(1,21):
print "第",i,"个月"
num1 = num2
num2 = sum
sum = num1+num2
print "有", sum, "个兔子" #后一个月兔子的数量为前两个月兔子数量之和
print "一共有",sum,"个兔子"
#小明有一美元要买（1-100美分）东西，求出找零最少的情况
--------------找零钱-----------------
buy = input('请输入买糖的价格1-100：')
count = 0
for a in range(0,5): #25美分面额的 不能超过4张 （25×5>100）
for b in range(0,3): #10美分面额的 不能超过2张 （10×3>25）这时可以给一张25美分面额的替代了
for c in range(0,2): # 5美分面额的 不能超过1张 （5×2=10） 这时可以用一张10美分面额的替代了
for d in range(0,5): #1美分的 不能超过4张 （1×5=5） 这时可以给一张5 美分面额的替代
if a*25+b*10+c*5+d*1+buy == 100 and 10*b+5*c!=25 and 5*d+c!=10:
count = a + b + c + d
print '找零%d个25美分 %d个10美分 %d个5美分 %d个1美分'%(a, b, c, d)
print '一共', count, '个硬币'
---------------乘法口诀表--------------------
for i in range(1,10):
for j in range(1,i+1):
if i*j<10:
print i, '×', j, '=', i * j, ' ',
else:
print i,'×',j ,'=', i*j,'',
print ''
四、函数
-----------------输出不定个数的数字的和-------------
sum_b = 0
sum_c = 0
sum_d = 0
def functionC(x,y,*args,**kwargs):
global sum_d
sum_b = x+y
sum_c= sum(args) #求和函数sum()必须传入可迭代对象
sum_d = sum_c+sum_b
return sum_d
functionC(1,2,3,4,5,6,7,8,9,10)
print sum_d
------------模拟range（）全功能----------------
list_input = [2,9] #手动调制输入的range()
def range_1(*args):
if len(list_input)==1: #输入一个数字时
x0 = list_input[0]
list_output = []
i = 0
while x0>1 and i<x0:
list_output.append(i)
i+=1
else:
print '输入的数字必须大于1'
return list_output
elif len(list_input)==2: #输入二个数字时
x0 = list_input[0]
x1 = list_input[1]
list_output = []
i = x0
if x0<x1:
while x1>0 and i<x1:
list_output.append(i)
i+=1
return list_output
else:
print('输入错误')
elif len(list_input)==3: #输入三个数字时
x0 = list_input[0]
x1 = list_input[1]
x3 = list_input[2]
list_output = []
i = x0
if x0<x1 and x3<x1:
while x1>1 and i<x1:
list_output.append(i)
i+=x3
return list_output
else:
print('输入错误')
else:
print '你又调皮了，最多只能输入三个'
print range_1(list_input)
-----------遍历计算字符串的长度----------
list_a = []
j = 0
def str_x(str_a):
for i in str_a:
global j #使用全局变量计数
list_a.append(i)
j+=1
return j
str_a =list(raw_input('请输入字符串：'))
str_x(str_a)
print j
------------计算传入数字的各个位数之和------------
def item_sum(x):
if str1<0: #输入的数小于零时
abs(str1) #取绝对值
list_sum = []
str2 = str(x)
for item in str2:
list_sum.append(int(item))
elif str1>0:
list_sum = []
str2 = str(x)
for item in str2:
list_sum.append(int(item))
return sum(list_sum)
else:
return 0
str1 = 3418291283 #传入数字转成字符串 / 传入数字型字符串
print item_sum(str1)
-----------------互不相同且无重复数字的三位数----------------
count = 0
list_b = 0
def third_num(list_a):
list_len = []
global count
for i in list_a:
for j in list_a:
for k in list_a:
if i!=j and j!=k and i!=k:
list_b =str(i)+str(j)+str(k)
list_len.append(list_b)
count+=1
return list_len
list_a = [1,2,3,4]
print third_num(list_a)
print '三位数个数：',count
----------------判断这一天是这一年的第几天----------------------
def day_in_year(year_n,month_n,day_n):
run = [31,29,31,30,31,30,31,31,30,31,30,31] #闰年，二月份天数不能大于29
ping = [31,28,31,30,31,30,31,31,30,31,30,31] #非闰年，二月份天数不能大于28
if year_n>= 1 and 12>=month_n>= 1 and 32>day_n>= 1:
if year_n % 4 == 0 and year_n % 100 != 0 or year_n % 400==0:
day_n = sum(run[:month_n-1])+day_n
return day_n
else:
day_n = sum(ping[:month_n-1])+day_n
return day_n
else:
print '输入格式错误'
year_n, month_n,day_n= int(raw_input('请输入年')),int(raw_input('请输入月')),int(raw_input('请输入日'))
print day_in_year(year_n,month_n,day_n)
----------------不使用sort()完成对任意list的升序和降序的排列------------------- #冒泡排序
list7 = [2,5,6,1,4,9,]
def sort_num(*args):
list8 = []
for i in range(len(list7)):
for j in range(len(list7)-1):
if list7[i]<list7[j]:
list7[j],list7[i] = list7[i],list7[j] #直接交换
list8 = list7
return list8
print '升序结果：',sort_num(list7)
-----------对元组内数字型元素求和----------------
def fun(num1,num2,*agrs,**kwargs):
sum1 = 0
sum2 = 0
sum0 = int(num1.strip())+int(num2)
for i in agrs:
if str(i).strip().isdigit():
sum1 += int(i)
for j in kwargs.values():
if str(j).strip().isdigit():
sum2 += int(j)
num3 = sum0+sum1+sum2
return num3
a = fun(' 1', 2, 3, ' 4', 5, 'hello', a1=2, b1=3)
print a
--------------字典合并----------------
def merge_two_dicts(x, y):
dict3 = {}
dict3 = dict1.copy()
dict3.update(dict2)
return dict3
dict1 = {'a':1,'b':2,'c':3,'d':'hello'}
dict2 = {'a':2,'b':'2','c':'she','e':'10','f':4}
print(merge_two_dicts(dict1,dict2))
