首先,在oracle中效率排行:表连接>exist>not exist>in>not in,而且使用in查询会有查询条件数量不能超过1000的限制;因此如果简单提高效率可以用exist代替in进行操作,当然换成表连接可以更快地提高效率,具体是用left join代替not in 和not exist,用inner join 代替in和exist,这样可以大大提高效率。具体例子如下:

比如: 

(1)

SELECT PUB_NAME 

FROM PUBLISHERS

WHERE PUB_ID NOT IN (SELECT PUB_ID FROM TITLES WHERE TYPE = 'BUSINESS')

可以改写成: 

SELECT A.PUB_NAME 

FROM PUBLISHERS A LEFT JOIN TITLES B ON B.TYPE = 'BUSINESS' AND A.PUB_ID=B. PUB_ID
WHERE B.PUB_ID IS NULL

(2)

SELECT TITLE 

FROM TITLES

WHERE NOT EXISTS (SELECT TITLE_ID FROM SALES WHERE TITLE_ID = TITLES.TITLE_ID)

可以改写成:

SELECT TITLE 

FROM TITLES LEFT JOIN SALES ON SALES.TITLE_ID = TITLES.TITLE_ID

WHERE SALES.TITLE_ID IS NULL

如果保证子查询没有重复 ,IN、EXISTS的相关子查询可以用INNER JOIN 代替。

比如:

SELECT PUB_NAME 

FROM PUBLISHERS

WHERE PUB_ID IN (SELECT PUB_ID FROM TITLES

WHERE TYPE = 'BUSINESS')

可以改写成:
 

SELECT DISTINCT A.PUB_NAME 

FROM PUBLISHERS A INNER JOIN TITLES B ON B.TYPE = 'BUSINESS' AND A.PUB_ID=B. PUB_ID