java数字出现次数 统计数字出现的次数java

编写程序，读取1~100之间的整数，然后计算每个数出现的次数。假定输入0表示结束。

注意：如果一个数出现的次数大于一次，则在输出是使用“times”。以升序显示数字。 

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package pack2;

import java.util.Map.Entry;
import java.util.Scanner;
import java.util.Set;
import java.util.TreeMap;

public class Count {

	public static void main(String[] args) {
		try(Scanner input = new Scanner(System.in);) {
			count2(input);
		}
	}

	/**计算数字的出现次数（方法一）*/
	public static void count2(Scanner input) {
		TreeMap<Integer, Integer> map = new TreeMap<>();
		int integer;
		
		System.out.print("Enter the integers between 1 and 100: ");
		do {
			integer = input.nextInt();
			if(integer != 0)
				if(!map.containsKey(integer))
					map.put(integer, 1);
				else 
					map.put(integer, map.get(integer) + 1);
		}while(integer != 0);
		
		Set<Entry<Integer, Integer>> set = map.entrySet();
		for (Entry<Integer, Integer> entry : set) {
			System.out.println(entry.getKey()+" occurs "+entry.getValue()+ 
                                 (entry.getValue() == 1 ? " time" : " times"));
		}
	}

	/**计算数字的出现次数（方法二）*/
	public static void count1(Scanner input) {
		int[] array = new int[100];
		int integer;
		
		System.out.print("Enter the integers between 1 and 100: ");
		do {
			integer = input.nextInt();
			if(integer != 0)
				array[integer - 1]++;
		}while(integer != 0);
		
		for (int i = 0; i < array.length; i++) 
			if(array[i] != 0)
				System.out.println((i + 1)+" occurs "+array[i]+(array[i] == 1 ? " time" 
                                     : " times"));
	}
	
}

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