python 文件树状 gui python 树形列表

因为Python列表中的元素可以是列表，所以可以使用列表构建树形结构。

构建指定层数的满二叉树：

def build_tree_depth(tree, n, m, data):#data是结点的数据，构造指定层数的满二叉树
	#控制层数
	if n == m - 1:
		tree.append(data)
		return data
	else:
		tree.append(data)
		tree.append([])#创建左子树
		data += 1#改变结点的值（这里只是一个实例而已）
		data = build_tree_depth(tree[1], n+1, m, data)#递归实现创建

		tree.append([])#创建右子树
		data += 1
		data = build_tree_depth(tree[2], n+1, m, data)#递归实现创建
	return data

if __name__ == '__main__':
	tree = []
	n = 0
	m = 4
	data = 0
	build_tree_depth(tree, n, m, data)#n,m控制数的层数，data为结点的数据
	print(tree)

[0, [1, [2, [3], [4]], [5, [6], [7]]], [8, [9, [10], [11]], [12, [13], [14]]]]
[Finished in 0.2s]

 

搜索满二叉树：

def search_tree_depth(tree, data):#深度优先遍历
	data.append(tree[0])#data记录各个结点的数值
	if len(tree) != 1:#递归实现
		search_tree_depth(tree[1], data)
		search_tree_depth(tree[2], data)
	return 0

if __name__ == '__main__':
	tree = []
	n = 0
	m = 4
	data = 0
	build_tree_depth(tree, n, m, data)#n,m控制数的层数，data为结点的数据


	data_search = []
	search_tree_depth(tree, data_search)
	print(data_search)

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
[Finished in 0.2s]

 

搜索某一路径下的结点：

 上面我们创建的二叉树如下：

我们希望得到路径：0,1,2之后的结点，或路径0,1之后的结点：

def search_leaf(tree, data, road, result):#搜索某一路径下的任意结点
	road.append(tree[0])
	if len(tree) != 1:
		search_leaf(tree[1], data, road, result)
		search_leaf(tree[2], data, road, result)
	else:
		if road[:len(data)] == data[:]:
			result.append(tree[0])
			del(road[-1])
			return 0
	del(road[-1])
	return 0

if __name__ == '__main__':
	tree = []
	n = 0
	m = 4
	data = 0
	build_tree_depth(tree, n, m, data)#n,m控制数的层数，data为结点的数据


	data_search = []
	search_tree_depth(tree, data_search)
	
	data = [0, 1, 2]
	road = []
	result = []
	search_leaf(tree, data, road, result)
	print(result)

	data = [0, 1]
	road = []
	result = []
	search_leaf(tree, data, road, result)
	print(result)

[3, 4]
[3, 4, 6, 7]
[Finished in 0.2s]