LeetCode-Java-136. Single Number

题目

Given a non-empty array of integers, every element appears twice except for one. Find that single one.

Note:

Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

Example 1:

Input: [2,2,1]
Output: 1
Example 2:

Input: [4,1,2,1,2]
Output: 4

代码

其核心在于，任何数和自身异或之后都为0

class Solution {
    public int singleNumber(int[] nums) {
        int result = 0;
        for(int x:nums){
            result ^=x;
        }
        return result;
    }
}