oracle 树查询----select...start with....connect by....prior
- 创建表
create table test
(
id integer not null,
var varchar2(20),
par_id integer, ------父节点
level integer ------树的级别
);
create table test
(
id integer not null,
var varchar2(20),
par_id integer, ------父节点
level integer ------树的级别
);tips: 顶级父节点的par_id 建议设置为0;
- 查询操作
- 查询所有顶级父节点
sql select * from test where par_id = 0; - 查询儿子节点
select * from test where par_id = :1;
select * from test where par_id = :1;- 查询某节点所有后代
select * from test start with id = :1 connect by par_id = prior id;
select * from test start with id = :1 connect by par_id = prior id;- 查找一个节点的直属父节点(父亲)
SELECT b.* FROM test a JOIN test b ON a.par_id = WHERE = :1;
SELECT b.* FROM test a JOIN test b ON a.par_id = WHERE = :1;- 查找一个节点的所有直属父节点(祖宗)
SELECT * FROM test START WITH id = :1 CONNECT BY PRIOR par_id = id;
SELECT * FROM test START WITH id = :1 CONNECT BY PRIOR par_id = id;- 查询一个节点的兄弟节点(亲兄弟)
select a.* from test a where exists(select * from test b where a.par_id = b.par_id and = :1);
select a.* from test a where exists(select * from test b where a.par_id = b.par_id and = :1);- 查询与一个节点同级的节点(族兄弟)。 如果在表中设置了级别的字段,上表中的level,那么在做这类查询时会很轻松,同一级别的就是与那个节点同级的,在这里列出不使用该字段时的实现!
with tmp as
(select a.*, level lev from test a
start with a.par_id = 0 connect by a.par_id = prior )
select * from tmp where lev = (select lev from tmp where id = :1);
with tmp as
(select a.*, level lev from test a
start with a.par_id = 0 connect by a.par_id = prior )
select * from tmp where lev = (select lev from tmp where id = :1);- 更深层查询
-- 创建表
CREATE TABLE flfl
(
id NUMBER NOT NULL,
mc NVARCHAR2(20),
fljb NUMBER,
sjflid NUMBER
);
-- 创建表
CREATE TABLE flfl
(
id NUMBER NOT NULL,
mc NVARCHAR2(20),
fljb NUMBER,
sjflid NUMBER
);- 查询一个节点的父节点的的兄弟节点(伯父与叔父)
WITH tmp
AS (SELECT flfl.*,
LEVEL lev
FROM flfl
START WITH sjflid IS NULL
CONNECT BY sjflid = PRIOR id) SELECT b.*
FROM tmp b,
(SELECT *
FROM tmp
WHERE id = 7004
AND lev = 2) a
WHERE b.lev = 1
UNION ALL
SELECT *
FROM tmp
WHERE sjflid = (SELECT DISTINCT
FROM tmp x,
tmp y,
(SELECT *
FROM tmp
WHERE id = 7004
AND lev > 2) z
WHERE = z.sjflid
AND = y.sjflid);
WITH tmp
AS (SELECT flfl.*,
LEVEL lev
FROM flfl
START WITH sjflid IS NULL
CONNECT BY sjflid = PRIOR id) SELECT b.*
FROM tmp b,
(SELECT *
FROM tmp
WHERE id = 7004
AND lev = 2) a
WHERE b.lev = 1
UNION ALL
SELECT *
FROM tmp
WHERE sjflid = (SELECT DISTINCT
FROM tmp x,
tmp y,
(SELECT *
FROM tmp
WHERE id = 7004
AND lev > 2) z
WHERE = z.sjflid
AND = y.sjflid);这里查询分成以下几步。首先,将第7个一样,将全表都使用临时表加上级别;其次,根据级别来判断有几种类型,以上文中举的例子来说,有三种情况:(1)当前节点为顶级节点,即查询出来的lev值为1,那么它没有上级节点,不予考虑。(2)当前节点为2级节点,查询出来的lev值为2,那么就只要保证lev级别为1的就是其上级节点的兄弟节点。(3)其它情况就是3以及以上级别,那么就要选查询出来其上级的上级节点(祖父),再来判断祖父的下级节点都是属于该节点的上级节点的兄弟节点。 最后,就是使用UNION将查询出来的结果进行结合起来,形成结果集。
- 查询一个节点的父节点的同级节点(族叔)
WITH tmp
AS (SELECT a.*,
LEVEL lev
FROM flfl a
START WITH a.sjflid IS NULL
CONNECT BY a.sjflid = PRIOR )
SELECT *
FROM tmp
WHERE lev = (SELECT lev
FROM tmp
WHERE id = 819394) - 1
WITH tmp
AS (SELECT a.*,
LEVEL lev
FROM flfl a
START WITH a.sjflid IS NULL
CONNECT BY a.sjflid = PRIOR )
SELECT *
FROM tmp
WHERE lev = (SELECT lev
FROM tmp
WHERE id = 819394) - 1- 名称要列出名称全部路径。
这里常见的有两种情况,一种是是从顶级列出,直到当前节点的名称(或者其它属性);一种是从当前节点列出,直到顶级节点的名称(或其它属性)。举地址为例:国内的习惯是从省开始、到市、到县、到居委会的,而国外的习惯正好相反。
从顶部开始:
SELECT Sys_connect_by_path (mc, '/')
FROM flfl
WHERE id = 6498
START WITH sjflid IS NULL
CONNECT BY sjflid = PRIOR id;
SELECT Sys_connect_by_path (mc, '/')
FROM flfl
WHERE id = 6498
START WITH sjflid IS NULL
CONNECT BY sjflid = PRIOR id;从当前节点开始:
SELECT Sys_connect_by_path (mc, '/')
FROM flfl
START WITH id = 6498
CONNECT BY PRIOR sjflid = id;
SELECT Sys_connect_by_path (mc, '/')
FROM flfl
START WITH id = 6498
CONNECT BY PRIOR sjflid = id;sys_connect_by_path函数就是从start with开始的地方开始遍历,并记下其遍历到的节点,start with开始的地方被视为根节点,将遍历到的路径根据函数中的分隔符,组成一个新的字符串,这个功能还是很强大的。
- 列出当前节点的根节点。
SELECT connect_by_root mc,
flfl.*
FROM flfl
START WITH id = 6498
CONNECT BY PRIOR sjflid = id;
SELECT connect_by_root mc,
flfl.*
FROM flfl
START WITH id = 6498
CONNECT BY PRIOR sjflid = id;connect_by_root函数用来列的前面,记录的是当前节点的根节点的内容。
- 列出当前节点是否为叶子。
SELECT connect_by_isleaf,
flfl.*
FROM flfl
START WITH sjflid IS NULL
CONNECT BY sjflid = PRIOR id;
SELECT connect_by_isleaf,
flfl.*
FROM flfl
START WITH sjflid IS NULL
CONNECT BY sjflid = PRIOR id;connect_by_isleaf函数用来判断当前节点是否包含下级节点,如果包含的话,说明不是叶子节点,这里返回0;反之,如果不包含下级节点,这里返回1
















