Given a linked list, rotate the list to the right by k places, where k is non-negative.

Example 1:

Input: 1->2->3->4->5->NULL, k = 2
Output: 4->5->1->2->3->NULL
Explanation:
rotate 1 steps to the right: 5->1->2->3->4->NULL
rotate 2 steps to the right: 4->5->1->2->3->NULL
Example 2:

Input: 0->1->2->NULL, k = 4
Output: 2->0->1->NULL
Explanation:
rotate 1 steps to the right: 2->0->1->NULL
rotate 2 steps to the right: 1->2->0->NULL
rotate 3 steps to the right: 0->1->2->NULL
rotate 4 steps to the right: 2->0->1->NULL

/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* rotateRight(ListNode* head, int k) {


if (k==0) return head;
if(head==NULL) return NULL;


ListNode* p=head;
ListNode* pre=head;

int length=1;
int rot;
while(p->next) {p=p->next; length++;}
p->next=head; //构成一个环
rot=length>k?length-k-1:length-k%length-1;

while(rot--) pre=pre->next;
p=pre->next;
cout<<p->val<<endl;
pre->next=NULL;
return p;


}
};