LeetCode之First Unique Character in a String

1、题目

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.

Examples:

s = "leetcode"
return 0.

s = "loveleetcode",
return 2.

 

2、代码实现

public class Solution {
    public int firstUniqChar(String s) {
		if (s == null || s.length() == 0) {
			return -1;
		}
		HashMap<Character, Integer> map = new HashMap<Character, Integer>();
		for (int i = 0; i < s.length(); i++) {
			Integer in = map.get(s.charAt(i));
			if (in == null) 
				map.put(s.charAt(i), 1);
			else
				map.put(s.charAt(i), 2);
		}
		for (int i = 0; i < s.length(); i++) {
			if(map.get(s.charAt(i)) == 2) {
				continue;
			} else {
				if (map.get(s.charAt(i)) == 1) {
					return i;
				}
			}
		} 
		return -1;
	}
}

 

 

 

3、总结

一般看到求数组里面唯一元素，和字符串里面唯一元素，我们可以通过HashMap来解决，每个字符或者元素作为key,然后出现一次设置一个value1,出现2次以上设置一个统一的value2,最后通过遍历得到value1,来解决问题