python for 递减 python递减循环

#theta = theta - alpha*(theta*X-Y)*X
theta = 1.0
#(alpha 阿尔法)
alpha = 0.1
#100次遍历
for i in range(100):
    #sum/3.0表示求加权平均值
    theta = theta + np.sum(alpha*(Y-dot(X,theta))*X)/3.0
print(theta)

3.打印结果：

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接下来这段原码是实现100，从100递减执行

j = 79
        for i in range(79):
            the_date = datetime.date.today()
            yesterday = the_date - datetime.timedelta(days=j)
            currentDate = yesterday
            start_date = currentDate
            end_date = currentDate
            yesterday = start_date - datetime.timedelta(days=1)
            # 当前时间戳-日志查询结束时间
            startTimeStamp = int(time.mktime(time.strptime(str(start_date), "%Y-%m-%d")))
            endTimeStamp = startTimeStamp + 86399
            print("数据开始时间：", start_date)
            print("数据结束时间：", end_date)
            print("开始时间戳：", startTimeStamp)
            print("结束时间戳：", endTimeStamp)
            print("昨日日期：", yesterday)
            j -= 1
            print("jjjjjjjjjjjj:", j)
            print()
            print()
            print()