ID a 
1 3 
2 4 
3 4 
4 7 
5 7 

累计求和 为以下形式
ID a b
1 3 3
2 4 7
3 4 11
4 7 18
5 7 25

SELECT 
    ID,
    a,
    (SELECT SUM(a) FROM tb WHERE ID<=A.ID) AS b
FROM tb AS A