find_first_of 源码剖析
原创
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函数原型:
equality (1)
template <class ForwardIterator1, class ForwardIterator2>
ForwardIterator1 find_first_of (ForwardIterator1 first1, ForwardIterator1 last1,
ForwardIterator2 first2, ForwardIterator2 last2);
predicate (2)
template <class ForwardIterator1, class ForwardIterator2, class BinaryPredicate>
ForwardIterator1 find_first_of (ForwardIterator1 first1, ForwardIterator1 last1,
ForwardIterator2 first2, ForwardIterator2 last2,
BinaryPredicate pred);
功能:
在区间[ first1 , last1 )里找到第一个可以与区间[ first2 , last2 )任意的某个值匹配的元素,返回其迭代器,找不到返回last1。
例子:
// find_first_of example
#include <iostream> // std::cout
#include <algorithm> // std::find_first_of
#include <vector> // std::vector
#include <cctype> // std::tolower
bool comp_case_insensitive (char c1, char c2) {
return (std::tolower(c1)==std::tolower(c2));
}
int main () {
int mychars[] = {'a','b','c','A','B','C'};
std::vector<char> haystack (mychars,mychars+6);
std::vector<char>::iterator it;
int needle[] = {'A','B','C'};
// using default comparison:
it = find_first_of (haystack.begin(), haystack.end(), needle, needle+3);
if (it!=haystack.end())
std::cout << "The first match is: " << *it << '\n';
// using predicate comparison:
it = find_first_of (haystack.begin(), haystack.end(),
needle, needle+3, comp_case_insensitive);
if (it!=haystack.end())
std::cout << "The first match is: " << *it << '\n';
return 0;
}
运行如下:
The first match is: A
The first match is: a
// TEMPLATE FUNCTION find_first_of WITH PRED
template<class _FwdIt1,
class _FwdIt2,
class _Pr> inline
_FwdIt1 _Find_first_of(_FwdIt1 _First1, _FwdIt1 _Last1,
_FwdIt2 _First2, _FwdIt2 _Last2, _Pr _Pred)
{ // look for one of [_First2, _Last2) satisfying _Pred with element
for (; _First1 != _Last1; ++_First1)
for (_FwdIt2 _Mid2 = _First2; _Mid2 != _Last2; ++_Mid2)
if (_Pred(*_First1, *_Mid2))
return (_First1);
return (_First1);
}
template<class _FwdIt1,
class _FwdIt2,
class _Pr> inline
_FwdIt1 find_first_of(_FwdIt1 _First1, _FwdIt1 _Last1,
_FwdIt2 _First2, _FwdIt2 _Last2, _Pr _Pred)
{ // look for one of [_First2, _Last2) satisfying _Pred with element
_DEBUG_RANGE(_First1, _Last1);
_DEBUG_RANGE(_First2, _Last2);
_DEBUG_POINTER_IF(_First1 != _Last1 && _First2 != _Last2, _Pred);
return (_Rechecked(_First1,
_Find_first_of(_Unchecked(_First1), _Unchecked(_Last1),
_Unchecked(_First2), _Unchecked(_Last2), _Pred)));
}
源码摘抄自Visual Studio 2015安装目录algorithm文件中。
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