题目大意：根据题目将字符串进行转换
解体思路：找到所需要替换的内容，存储在字符串中，再进行输出
#include<cstdio>
#include<cstring>
int main() {
char str[300];
char s[3000];
char *st[100];
int number;
int len;
int mark = 0;
int i;
int test;
scanf("%d\n", &test);
for(int i = 0 ; i < test * 2; i++) {
gets(str);
strcat(s,str);
s[strlen(s)] = '\n';
}
len = strlen(s);
char s1[100], s2[100], s3[100], s4[100] ;
memset(s2,'\0',sizeof(s2));
memset(s3,'\0',sizeof(s3));
memset(s4,'\0',sizeof(s4));
memset(s1,'\0',sizeof(s1));
for( i = 0 ; i < len ; i++ ) {
if(mark != test) {
if(s[i] == '<') {
int k = i;
k++;//跳过字符<
for(int j = 0; s[k] != '>' ; j++, k++) {
s1[j] = s[k];
}
k++;//跳过字符>
for(int j = 0; s[k] != '<'; j++,k++ )
s2[j] = s[k];
for( ; k < len; k++ ) {
if(s[k] == '<') {
k++;//跳过字符<
for(int j = 0; s[k] != '>' ; k++, j++) {
s3[j] = s[k];
}
k++;//跳过字符>
for(int j = 0; s[k] != '\n'; j++, k++ )
s4[j] = s[k];
break;
}
}
printf("%s%s%s%s", s1, s2, s3,s4);
i = k;
}
if(s[i] == '.' && s[i + 1] == '.' && s[i + 2] == '.') {
i = i + 3;
printf("%s%s%s%s",s3 ,s2, s1, s4);
mark++;
memset(s2,'\0',sizeof(s2));
memset(s3,'\0',sizeof(s3));
memset(s4,'\0',sizeof(s4));
memset(s1,'\0',sizeof(s1));
if(mark == test) {//少了这个就多出了个空格
printf("\n");
return 0;
}
}
}
printf("%c",s[i]);
}
return 0;
}
