People in Mars（火星） represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for ​​Red​​​, the middle 2 digits for ​​Green​​​, and the last 2 digits for ​​Blue​​. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input Specification:

Each input file contains one test case which occupies a line containing the three decimal color values.

Output Specification:

For each test case you should output the Mars RGB value in the following format: first output ​​#​​​, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a ​​0​​ to its left.

Sample Input:

15 43 71

Sample Output:

#123456

参考代码：

#include<cstdio>
char RGB[13] ={'0', '1', '2', '3', '4', '5', '6', '7',
'8', '9', 'A', 'B', 'C'};
int main(int argc, char const *argv[])
{
  int a, b, c;
  scanf("%d%d%d", &a, &b, &c);
  printf("#");
  printf("%c%c", RGB[a / 13], RGB[a % 13]);
  printf("%c%c", RGB[b / 13], RGB[b % 13]);
  printf("%c%c\n", RGB[c / 13], RGB[c % 13]);
  return 0;
}

推荐代码：

#include<cstdio>
char RGB[13] ={'0', '1', '2', '3', '4', '5', '6', '7',
'8', '9', 'A', 'B', 'C'};
void res(int x){
  int z[10] ,num = 0;
  if(x < 13) printf("0");
  do {
    z[num++] = x % 13;
    x /=  13;
  }while(x != 0);

  for (int i = num -1; i >= 0; --i)
  {
    printf("%c", RGB[z[i]]);
  }
}
int main(int argc, char const *argv[])
{
  int a, b, c;
  scanf("%d%d%d", &a, &b, &c);
  printf("#");
  res(a);
  res(b);
  res(c);

  printf("\n");
  return 0;
}