1.使用asp.net将图片上传并存入SQL Server中,然后从SQL Server中读取并显示出来:
1)上传并存入SQL Server
数据库结构
create table test
{
id identity(1,1),
FImage image
}
相关的存储过程
Create proc UpdateImage
(
@UpdateImage Image
)
As
Insert Into test(FImage) values(@UpdateImage)
GO
<input id="UpPhoto" name="UpPhoto" runat="server" type="file">
<asp:Button id="btnAdd" name="btnAdd" runat="server" Text="上传"></asp:Button>
private void btnAdd_Click(object sender, System.EventArgs e)
{
//获得图象并把图象转换为byte[]
HttpPostedFile upPhoto=UpPhoto.PostedFile;
int upPhotoLength=upPhoto.ContentLength;
byte[] PhotoArray=new Byte[upPhotoLength];
Stream PhotoStream=upPhoto.InputStream;
PhotoStream.Read(PhotoArray,0,upPhotoLength);
SqlConnection conn=new SqlConnection();
conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";
cmd.CommandType=CommandType.StoredProcedure;
cmd.Parameters["@UpdateImage"].Value=PhotoArray;
//string strSql="Insert into test(FImage) values(@FImage)";
//SqlCommand cmd=new SqlCommand(strSql,conn);
//cmd.Parameters.Add("@FImage",SqlDbType.Image);
//cmd.Parameters["@FImage"].Value=PhotoArray;
cmd.ExecuteNonQuery();
conn.Close();
}
在需要显示图片的地方添加如下代码:
<asp:image id="imgPhoto" runat="server" ImageUrl="ShowPhoto.aspx"></asp:image>
private void Page_Load(object sender, System.EventArgs e)
{
if(!Page.IsPostBack)
{
SqlConnection conn=new SqlConnection()
conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";
SqlCommand cmd=new SqlCommand(strSql,conn);
SqlDataReader reader=cmd.ExecuteReader();
reader.Read();
Response.BinaryWrite((Byte[])reader["FImage"]);
Response.End();
reader.Close();
}
}
2.在WinForm中将图片存入SQL Server,并从SQL Server中读取并显示在picturebox中
数据库结构和使用的存储过过程,同上面的一样
首先,在窗体中加一个OpenFileDialog控件,命名为ofdSelectPic ;
然后,在窗体上添加一个打开文件按钮,添加如下单击事件代码:
Stream ms;
byte[] picbyte;
//ofdSelectPic.ShowDialog();
if (ofdSelectPic.ShowDialog()==DialogResult.OK)
{
if ((ms=ofdSelectPic.OpenFile())!=null)
{
//MessageBox.Show("ok");
picbyte=new byte[ms.Length];
ms.Position=0;
ms.Read(picbyte,0,Convert.ToInt32(ms.Length));
//MessageBox.Show("读取完毕!");
SqlConnection conn=new SqlConnection();
conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";
cmd.CommandType=CommandType.StoredProcedure;
cmd.Parameters["@UpdateImage"].Value=picbyte;
cmd.ExecuteNonQuery();
conn.Close();
}
}
首先,添加一个picturebox,名为ptbShow
然后,添加一个按钮,添加如下响应事件:
SqlConnection conn=new SqlConnection();
conn.ConnectionString="Data Source=localhost;Database=test;User Id=sa;Pwd=sa";
SqlDataReader reader=cmd.ExecuteReader();
reader.Read();
Image image=Image.FromStream(ms,true);
conn.Close();