将两个列表元素一一对应成字典

方法1 dict( (k, v) for k, v in zip)

https://www.cnblogs.com/shenxiaolin/p/11268597.html

names = ['n1','n2','n3']
values = [1,2,3]

nvs = zip(names,values)
dict((name,value) for name, value in nvs)

注意:以下字典解析式报错

# {(name: value) for name, value in nvs}
# {name: value for name, value in nvs.items()}

方法2 dict( zip() )

dict(
    zip(
        df_tblCoilUnqualifiedCard.columns.tolist(),
        df_tblCoilUnqualifiedCard.values[0].tolist()
    )
)