将两个列表元素一一对应成字典
方法1 dict( (k, v) for k, v in zip)
names = ['n1','n2','n3']
values = [1,2,3]
nvs = zip(names,values)
dict((name,value) for name, value in nvs)
注意:以下字典解析式报错
# {(name: value) for name, value in nvs}
# {name: value for name, value in nvs.items()}
方法2 dict( zip() )
dict(
zip(
df_tblCoilUnqualifiedCard.columns.tolist(),
df_tblCoilUnqualifiedCard.values[0].tolist()
)
)