C++ 穷举算法求解鸡兔同笼问题

今有鸡兔同笼，上有三十五头，下有九十四足，问鸡兔几何？

#include <iostream>

using namespace std;
int scanning(int head, int foot, int* chicken, int* rabbit);
int main()
{
    int chicken, rabbit,head, foot;
    cout << "穷举法求解鸡兔同笼问题" << endl;
    cout << "请输入头数" << endl;
    cin >> head;
    cout << "请输入脚数" << endl;
    cin >> foot;
    if ((scanning(head, foot, &chicken, &rabbit))== 1)
    {
        cout << "鸡有:" << chicken << "只" << endl;
        cout << "兔有:" << rabbit << "只" << endl;
    }
    else
    {
        cout << "无解" << endl;
    }
    return 0;
}
int scanning(int head, int foot, int* chicken, int* rabbit)
{
    int re, i, j;
    re = 0;
    for (i = 0; i <= head; i++)
    {
        j = head - i;//当i为0时一共有j头,i+j=head;
        if (i * 2 + j * 4 == foot)
        {
            re = 1;
            *chicken = i;//如果条件满足，那就把i给鸡
            *rabbit = j;//如果条件满足，那就把j给兔
        }
    }
    return re;
}

换一种写法（双重循环）

//从0开始循环，万一全是兔子或者全是鸡呢对吧
for (i = 0; i <= head; i++)
    {
        for (j = 0; j <= foot; j++)
        {
            if ((i + j == head) && (i * 2 + j * 4 == foot))
            {
                re = 1;//标记
                *chicken = i;
                *rabbit = j;
            }
        }
    }

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