• (0, 0, { values }) link to a new record that needs to be created with the given values dictionary
• (1, ID, { values }) update the linked record with id = ID (write values on it)
• (2, ID) remove and delete the linked record with id = ID (calls unlink on ID, that will delete the object completely, and the link to it as well)
• (3, ID) cut the link to the linked record with id = ID (delete the relationship between the two objects but does not delete the target object itself)
• (4, ID) link to existing record with id = ID (adds a relationship)
• (5) unlink all (like using (3,ID) for all linked records)
• (6, 0, [IDs]) replace the list of linked IDs (like using (5) then (4,ID) for each ID in the list of IDs)
• If you want to link new record to existing wizards than yes, you need to use (6, 0, [IDS]). But if you want to create new wizards on the fly and link to this record than use 'fee_ids': [(0, 0, values1), (0, 0, values2) ]
懂得,原来世界如此简单!