Linux下批量添加/删除用户

转载自：http://linux5588.blog.51cto.com/65280/750836

运行结果如下：

[root@server1 shell.sh]# ./useradd.sh   
Please Input 1 or 2 :  
1) Add User  
2) Del User  
#? 1  
Please Input your username prefix:user  
Please Input your user number:10  
Please Enter your user password: 123  
Add user1 Sucessful!  
Add user2 Sucessful!  
Add user3 Sucessful!  
Add user4 Sucessful!  
Add user5 Sucessful!  
Add user6 Sucessful!  
Add user7 Sucessful!  
Add user8 Sucessful!  
Add user9 Sucessful!  
Add user10 Sucessful! 

以下是脚本内容：

#!/bin/bash  
#this scripts for batch add/del user  
#DATE:2011/9/25 AUTHOR:LEO Email:[e-mail]  
#if you are not root,exit  
ID=$(id -u)  
if [ $ID -ne 0 ];then  
 echo "Your are not root,only root can Add/Del user"  
 exit 1  
fi  
#define variables  
ADD="/usr/sbin/useradd"
DEL="/usr/sbin/userdel"
PASSWD="/usr/bin/passwd"
num=1
echo "Please Input 1 or 2 :"  
select var in "Add User" "Del User"  
do  
 break  
done  
read -p "Please Input your username prefix:" pre  
read -p "Please Input your user number:" user_num  
case $var in  
 "Add User")  
 read -p "Please Enter your user password: " PW  
 while [ $num -le $user_num ]  
 do  
  if [ -e /home/$pre$num -o -e /var/mail/$pre$num ]  
  then  
       echo "$pre$num already exists!!"  
num=$(expr $num + 1)  
  else  
   $ADD $pre$num && echo $PW | $PASSWD --stdin $pre$num &>/dev/null  
   if [ $? = 0 ];then   
    echo "Add $pre$num Sucessful!"   
   fi  
num=$(expr $num + 1)  
  fi  
 done  
 ;;  
 "Del User")  
 while [ $num -le $user_num ]  
 do  
    $DEL -r $pre$num &>/dev/null && echo "Delete $pre$num Sucessful" || echo "There is no $pre$num"  
num=$(expr $num + 1)  
 done  
 ;;  
 *)  
 echo "Invaild Input"  
esac