$arr = [[
    "objid" => "22249",
    "device" => "192.168.0.202",
    "datetime" => "2021/3/15 12:52:17",
    "datetime_raw" => 44270.2029801968,
    "sensor" => "内存1",
    "status" => "正常运行",
    "status_raw" => 3,
    "lastvalue" => "89",
    "lastvalue_raw" => "89"
], [
    "objid" => "22250",
    "device" => "192.168.0.202",
    "datetime" => "2021/3/15 12:52:17",
    "datetime_raw" => 44270.2029801968,
    "sensor" => "内存2",
    "status" => "正常运行",
    "status_raw" => 3,
    "lastvalue" => "74",
    "lastvalue_raw" => "89"
], [
    "objid" => "22250",
    "device" => "192.168.0.202",
    "datetime" => "2021/3/15 12:52:17",
    "datetime_raw" => 44270.2029801968,
    "sensor" => "内存2",
    "status" => "正常运行",
    "status_raw" => 3,
    "lastvalue" => "34",
    "lastvalue_raw" => "89"
]];
项目需求
遍历数据,求包含“内存”字段的lastvalue,求和。
for ($i = 0; $i < count($arr); $i++) {
    if (stripos($arr[$i]["sensor"], "内存") !== false) {
        $cpu[$i] = $arr[$i]["lastvalue"];
    }
}
echo "<pre>";
var_dump($cpu);
$data["cpu"] = round(array_sum($cpu) / count($cpu), 1);
lockdatav Done!
 
 
                     
            
        













 
                    

 
                 
                    