从上到下按层打印二叉树,同一层的节点按从左到右的顺序打印,每一层打印到一行。
例如:
给定二叉树: [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
返回其层次遍历结果:
[
[3],
[9,20],
[15,7]
]
提示:
节点总数 <= 1000
注意:本题与主站 102 题相同:https://leetcode-cn.com/problems/binary-tree-level-order-traversal/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrder(TreeNode* root) {
if (root == NULL)
return {};
queue<TreeNode*> q;
vector<vector<int>> res;
q.push(root);
while (!q.empty())
{
vector<int> level;
int size = q.size();
while (size--)
{
level.push_back(q.front()->val);
if (q.front()->left)
q.push(q.front()->left);
if (q.front()->right)
q.push(q.front()->right);
q.pop();
}
res.push_back(level);
}
return res;
}
};
















