【每日一题】【链表】2021年11月20日-21. 合并两个有序链表

将两个升序链表合并为一个新的 升序 链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。 

 

 

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode() {}
 *     ListNode(int val) { this.val = val; }
 *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }
 * }
 */
class Solution {
    public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
        ListNode dummy = new ListNode(0);
        ListNode cur = dummy;
        while(l1 != null && l2 != null) {
            if(l1.val < l2.val) {
                cur.next = l1;
                l1 = l1.next;
                cur = cur.next;
            } else {
                cur.next = l2;
                l2 = l2.next;
                cur = cur.next;
            }
        }
        if(l1 != null) {
            cur.next = l1;
        }
        if(l2 != null) {
            cur.next = l2;
        }
        return dummy.next;
    }
}

 

作者：哥们要飞​