continue 继续执行循环,break跳出循环。
[root@hunt1574 ~]# cat test2.sh
#!/bin/bash
for index in 1 2 3 4 5 6 7
do
if [ $index -le 3 ];then
echo "continue"
continue
fi
echo $index
if [ $index -ge 6 ];then
echo "break"
break
fi
done
[root@hunt1574 ~]# sh test2.sh
continue
continue
continue
4
5
6
break