continue 继续执行循环,break跳出循环。

[root@hunt1574 ~]# cat test2.sh
#!/bin/bash
for index in 1 2 3 4 5 6 7
        do
                if [ $index -le 3 ];then
                        echo "continue"
                        continue
                fi
             echo $index
                if [ $index -ge 6 ];then
                        echo "break"
                        break
                fi
        done

[root@hunt1574 ~]# sh test2.sh
continue
continue
continue
4
5
6
break