import java.util.Scanner;
//题目:输入一个整数n,求从1到n这n个整数的十进制表示中1出现的次数。
//例如输入12,从1到12这些整数中包含1 的数字有1,10,11和12,1一共出现了5次。
public class CiShu {
public static void main(String args[]) {
Scanner cin = new Scanner(System.in);
int a = cin.nextInt(); int result = 0;
for (int i = 1; i <= a; i++) {
result = result + contains1num(i); }
System.out.print(result);
} private static int contains1num(int num) {
int count = 0; for (int i = 0; i < 6; i++)// 统计的位数
{
if (num % Math.pow(10, i + 1) == Math.pow(10, i))
count++;
num = (int) (num - num % Math.pow(10, i + 1)); }
return count;
}
}