json序列化级联的问题

 方法一：用JsonConfig

 

Java代码

1. import net.sf.json.JSONObject;
2. import net.sf.json.JsonConfig;
3. //业务类
4. TblBaseDict dict = tblBaseDictBiz.findById(id);
5.  
6. JsonConfig cfg = new JsonConfig();
7. //忽略的属性，不转json
8. cfg.setExcludes(new String[]{"handler","hibernateLazyInitializer"});
9. log.info(JSONObject.fromObject(dict,cfg));
10.  
11. JSONObject.fromObject(dict,cfg).toString();</pre>
12. //实体类
13. @JsonIgnoreProperties(value={"handler","hibernateLazyInitializer"})
14. public class TblBaseDict extends BaseEntity

import net.sf.json.JSONObject;
import net.sf.json.JsonConfig;
//业务类	
    	TblBaseDict dict = tblBaseDictBiz.findById(id);

    	JsonConfig cfg = new JsonConfig();   
    	//忽略的属性，不转json 
    	cfg.setExcludes(new String[]{"handler","hibernateLazyInitializer"});  
    	log.info(JSONObject.fromObject(dict,cfg));
    	
    	JSONObject.fromObject(dict,cfg).toString();</pre>
//实体类 
@JsonIgnoreProperties(value={"handler","hibernateLazyInitializer"}) 
public class TblBaseDict extends BaseEntity

 

方法二： @JsonIgnore 注解 //org.codehaus.jackson.annotate.JsonIgnore

Java代码

1. @JsonIgnore
2. public Set<TemplateInfo> getTemplateInfos() {
3. return templateInfos;
4. }