1.

#1374848290

df -h

#1373845293

free -m

#1376945197

ifconfig

 

如何转换成

 

#2013-08-18 13:01:30

df -h

#2013-08-18 13:01:33

free -m

#2013-08-18 13:01:37

ifconfig

 

 echo "123456789"|awk '{print substr($0,2,3)}'
234

 

echo "#123456789"|awk '/^#/{$0="#"substr($0,2,3)}1'
#123

 

awk '/^#/{$0="#"strftime("%F %T",substr($0,2))}1'

 

awk -F# 'NF>1{$0="#"strftime("%F %T",$2)}1'

 

sed '/^#/{s///;s/.*/date -d @& +"%F %T"/e;s/^/#/}'

 

sed '/^#/{s/#//g;s/.*/date -d @& +"%F %T"/e}'

 

 

2.

字符串为:/10.0.2.2/xxx_com_xzzz/ceshi01/abc

希望截取以/作为分割最后两个字段

得到 ceshi01/abc

 

echo "/10.0.2.2/xxx_com_xzzz/ceshi01/abc"|awk -F'/' '{print $(NF-1)"/"$NF}'

 

 

 

1 a b c

2 a c

3 a b c

4 a c

 

要求:将其余列相同的,将第一列求和后合并

 

得到如下结果:

4 a b c

6 a c

 

awk  -F'a' '{a[$NF]+=$1}END{for(i in a){print a[i],"a"i}}'  1.txt

 

 

3.

http://bbs.chinaunix.net/thread-1853992-1-1.html 如何将竖排的数字横排

awk -F'>' '{if (/^[0-9]/){ORS=" ";print $0}else{ORS="\n";print "| "$2}}' f2.txt

awk '{printf /^[0-9].*/?$0" ":"| "substr($0,2)"\n"}' f2.txt

 

4.

http://bbs.chinaunix.net/thread-4096854-1-1.html 一段文本,求sed和awk截取方法 grep -Po '(?<=Address:)[^<]+'

或者awk -F '[^0-9.]+' '{print $2}'

或者awk -vRS='IP Address: ' 'NR>1{match($0,/[^<]+/,a);print a[0]}'  

 

5.

在一个文件的倒数第三行

添加一个字母a

文件的行数是不确实的

awk '{a[NR]=$0}END{for(i=1;i<=NR;i++){print a[i];if(i==NR-3)print "a"}}'

或者awk '{a[NR]=$0}END{for(i=1;i<=NR;i++){if(i==NR-3){print a[i]"\n$"}else{print a[i]}}}'

 

 

6.

http://bbs.chinaunix.net/thread-2288219-1-2.html awk实现grep -A3 -B3的效果,文本10G行

grep -B 5 "J"

 

 

7.

Mike Harrington:(510) 548-1278:250:100:175

Christian Dobbins:(408) 538-2358:155:90:201

Susan Dalsass:(206) 654-6279:250:60:50

Archie McNichol:(206) 548-1348:250:100:175

Jody Savage:(206) 548-1278:15:188:150

Guy Quigley:(916) 343-6410:250:100:175

Dan Savage:(406) 298-7744:450:300:275

NancyMcNeil:(206) 548-1278:250:80:75

John Goldenrod:(916) 348-4278:250:100:175

Chet Main:(510) 548-5258:50:95:135

Tom Savage:(408) 926-3456:250:168:200

Elizabeth Stachelin:(916) 440-1763:175:75:300

 

打印三个月捐献总额少于800 的人的姓名

awk  -F':' '{ if( $(NF-2) +$(NF-1) +$NF < 800) print $1}'

 

8.

cat file

base_forge_meta

lib_gvg_scene

lib_fbt_room

 

格式改成:

base_forge_meta.beam,lib_gvg_scene.beam,lib_fbt_room.beam

 

awk -vOFS='' '{$2=".beam";s=s?s","$0:$0}END{print s}'

或者awk '{a[NR]=$0}END{for(i=1;i<=NR;i++){if(i<NR){printf a[i]".beam,"}else{printf a[i]".beam\n"}}}'

或者awk -v ORS="," '{a[NR]=$0}END{for(i=1;i<=NR;i++){if(NR-i>0){print a[i]".beam"}else{print a[i]".beam\n"}}}'

 

9.

把b文件包含a文件手机号码的行打印出来

awk题目_shell

 

awk 'NR==FNR{a[$1];next}{for(i in a)if($NF~i)print}' a b

 

(http://bbs.chinaunix.net/thread-520411-1-1.html

grep -f fileb filea

 

while read i

do

grep $i a

done < b)

 

cat a

123

345

567

 

cat b

abc

nba

dda 123

dad 345

dsf 456

ads 567

 

awk 'NR==FNR{a[$1];next}{for(i in a)if($NF~i)print}' a b

dda 123

dad 345

ads 567

 

awk 'NR==FNR{a[$1]}NR>FNR{for(i in a)if($NF~i)print}' a b

dda 123

dad 345

ads 567

 

awk 'NR==FNR{a[$1]}NR>FNR{if($NF in a)print}' a b

dda 123

dad 345

ads 567

 

awk 'NR==FNR{a[$1]}{for(i in a)if($NF~i)print}' a b

123

345

567

dda 123

dad 345

ads 567

 

 

10.

cat file

112312412

124312312452100000

4231433234

1241

412141

14233423423

212189

98079076

79978

 

根据文本中最长位数的那行进行补齐,不足位数的后面补0。

awk 'NR==FNR{if(max<length($0))max=length($0);next}{while(length($0)<max)$0=$0"0"}1' file file

 

awk '{a[NR]=$0;if(max<length($0))max=length($0)}END{for(i=1;i<=NR;i++){while(length(a[i])<max)a[i]=a[i]"0";print a[i]}}' file


11.

要求

日期  时间   游戏名称   服数

 

curl -s "http://www.91wan.com/" | sed -r '/flf_fwli.*(none)?/!d;s/<[^>]*>/ /g' | column -t

 

elinks -dump -no-numbering http://www.91wan.com | grep -EB3 -x '[ ]+[0-9]+服' | xargs -n4 | column -t

 

12.

打印不足三行

awk '{s=s""$0}!(NR%3){print s;s=""}END{if(s)print s}'

或者xargs -n3

 

13.

下面文本内容:

dp:11:79484:101 205

dp:1:79484:101 17

dp:4:79484:101 11

合并变成一行,最后一列累加

dp:79484:101 233

 

awk 'BEGIN{FS="[ :]+";SUBSEP=":"}{a[$1,$3,$4]+=$5}END{for(i in a)print i,a[i]}'

 

a[$1":"$3":"$4]+=$5 改成这个,就不用SUBSEP

 

或者awk -F'[: ]' -v OFS=":" '{total+=$5}END{print $1,$3,$4,total}'

awk 'BEGIN{FS="[ :]+"}{a[$1":"$3":"$4]+=$5}END{for(i in a){split(i,a2,SUBSEP);print a2[1],a2[2],a2[3],a[i]}}'


14.

echo 192_168_66_1 |awk '{gsub("_",".")}1'

var=192_168_66_1;echo ${var//_/.} 这种方式也能变量替换


 

15.

cat file

aaa

bbb

ccc

aaa

111

222

aaa

333

444

 

第二次匹配aaa时取后2行

awk '/aaa/{m++;x=NR}m==2&&NR-x<=2&&NR-x>0'

或者awk '/aaa/{s++}s==2{for(i=1;i<=2;i++){getline;print}}'

(awk '/aaa/{s++}s==2{for(i=1;i<=2;i++){getline s;prints}}'

awk '/aaa/{s++}1&&s==2{for(i=1;i<=2;i++){getline;print}}'

awk '/aaa/{s++};s==2{for(i=1;i<=2;i++){getline;print}}'

awk '/aaa/{s++}{if(s==2){{for(i=1;i<=2;i++){getline;print}}}}'

)

 

(cat file

111

222

333

444

 

匹配222及下一行

awk '/222/{print $0;getline s;print s}'

222

333

 

awk '/222/{a=2}a--'

222

333

 

每隔两行在行尾回车并插入一个$符号

awk '{print;getline;print;print "$"}'

awk '{print;getline s;print s"\n$"}'

 

awk '1;(NR+1)%2{print "$"}'

awk 'NR%2{print $0};(NR+1)%2{print $0"\n$"}'

awk '{print $0}(NR+1)%2{print "$"}'

 

 awk '!(NR%2){print $0"\n$";next}1'

awk '{if(NR%2==0){print $0"\n$"}else{print $0}}'

awk '{if(NR%2==0){print gensub(/.*/,"&\n$","1")}else{print}}' 

 )

 

awk '/aaa/{m++;x=NR}m==2&&NR-x<=2' d

aaa

111

222

 

awk '/aaa/{m++;x=NR;print x}' d

1

4

7

 

awk '/aaa/{m++;x=NR}{print x,NR}' d

1 1

1 2

1 3

4 4

4 5

4 6

7 7

7 8    

7 9

 

awk '/aaa/{m++;x=NR}m==2' d

aaa

111

222

 

awk '/aaa/{m++;x=NR}{if(m==2)print $0}' d

aaa

111

222

 

awk '/aaa/{m++}{if(m==2)print $0}{for(i=1;i<=2;i++){getline;print $0}}' d

bbb
ccc
aaa
111
222
333
444

 

awk '/aaa/{m++}{if(m==2);print $0}{for(i=1;i<=2;i++){getline;print $0}}' d

aaa
bbb
ccc
aaa
111
222
aaa
333
444

 

awk '/aaa/{m++}{if(m==2){for(i=1;i<=2;i++){getline;print $0}}}' d
111
222

 

awk '/aaa/{m++;x=NR}m==2&&NR-x<=2&&NR-x>0' d

111

222

 

awk '/aaa/{m++;x=NR}m==2&&NR-x>0' d

 

111

222

 

awk '{for(i=1;i<=2;i++){getline;print $0}}' d

bbb

ccc

111

222

333

444

 

cat file

video

10.128.12.13

gamesvr

10.128.12.15

log

10.150.13.10

 

awk '{a[NR]=$0}/[0-9]/{next}{for(i=1;i<=NR;i++)print i,$0}' file

1 video

1 gamesvr

2 gamesvr

3 gamesvr

1 log

2 log

3 log

4 log

5 log

 

awk '{a[NR]=$0}/[0-9]/{next}{for(i in a){print i,$0}}' file

1 video

1 gamesvr

2 gamesvr

3 gamesvr

4 log

5 log

1 log

2 log

3 log

 

awk '{a[NR]=$0}/[0-9]/{next}{for(i in a){print i,a[1],a[3],a[5]}}' file

1 video  

5 video gamesvr

1 video gamesvr

2 video gamesvr

3 video gamesvr

4 video gamesvr log

5 video gamesvr log

1 video gamesvr log

2 video gamesvr log

3 video gamesvr log

16.

使用nmap扫描后得到的ip-mac片断如下:

Nmap scan report for 192.168.0.80

Host is up (0.00016s latency).

MAC Address: 60:A4:4C:A7:6C:51 (Unknown)

Nmap scan report for 192.168.0.84

Host is up (0.0084s latency).

MAC Address: 74:2F:68:BE:64:BF (Unknown)

Nmap scan report for 192.168.0.96

Host is up (0.00036s latency).

MAC Address: 60:A4:4C:A7:6C:9B (Unknown)

Nmap scan report for 192.168.0.97

Host is up (0.00036s latency).

MAC Address: 00:E0:66:75:A8:B1 (ProMax Systems)

怎样从这个文本文件中得到ip和对应的mac呢?

 

awk  '/report/{printf $NF;printf " "}/MAC/{print $3}' 2.txt

 

17.

cat data.txt如下内容

 

video

10.128.12.13

gamesvr

10.128.12.15

log

10.150.13.10

10.150.13.22

 

要实现样式结果如下

10.128.12.13       #video

10.28.12.15         #gamesvr

10.150.13.10       #log

10.150.13.22       #log

 

awk '/^[a-z]/{a="#"$0;next}{print $0,a}' file

或者awk '/[a-z]/{m="#"$0}/[0-9]/{print  $0,m}' file

 

awk '/[a-z]/{print $0}' file

video

gamesvr

log

 

awk '/[0-9]/{next}{print $0}' file

video

gamesvr

log

 

18.

有这样一个文件。

 

<version>v20130909195559<Version>

要求 20130909195559  对文本进行一次操作后数字自动加1

 

例如 结果是:<version>v20130909195560<Version>

echo '<version>v20130909195559<Version>' | awk 'BEGIN{RS="[0-9]+";ORS=OFS=""}{print $0,RT?RT+1:RT}'

或者awk 'BEGIN{ORS="";RS="[0-9]+"}NR==1{print $0(RT+1)}NR>1{print $0}'


19.


比如:

第一个文件:

10.124.0.1  000c.2980.001e

10.124.0.6  000c.2980.0561

第二个文件:

000c.2980.001e   GigabitEthernet1/18

000c.2980.0561   Port-channel1

 

要变成:

10.124.0.1  000c.2980.001e GigabitEthernet

1/18

10.124.0.6  000c.2980.0561 Port-channel1

 

awk  'NR==FNR{a[$2]=$0}NR>FNR{print a[$1],$2}'   a.txt b.txt

10.124.0.1  000c.2980.001e GigabitEthernet1/18

10.124.0.6  000c.2980.0561 Port-channel1

 

20.

echo {1..100}|awk '{for(;++i<=100;)j+=i;print j}'

echo {1..100}|awk '{for(i=1;i<=100;i++)j+=i;print j}'

 

echo {1..5}&& echo {1..4}&& echo {1..3} && echo {1..2}&& echo 1
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1

awk 'BEGIN{for(i=5;i>=1;i--){for(j=1;j<=i;j++)printf j" ";print " " }}'  

1 2 3 4 5  

1 2 3 4  

1 2 3  

1 2  

1  

 

awk 'BEGIN{for(i=5;i>=1;i--)printf i" ";print " "}'

5 4 3 2 1

 

awk 'BEGIN{i=5;for(j=1;j<=i;j++)printf j" ";print " "}'

1 2 3 4 5

 

21.

http://bbs.chinaunix.net/thread-4111833-1-1.html

 

cat file

Douglas Bates

   John Chambers

   Peter Dalgaard

   Seth Falcon

   Robert Gentleman

   Kurt Hornik

   Stefano Iacus

   Ross Ihaka

   Friedrich Leisch

   Uwe Ligges

   Thomas Lumley

   Martin Maechler

   Duncan Murdoch

   Paul Murrell

   Martyn Plummer

   Brian Ripley

   Deepayan Sarkar

   Duncan Temple Lang

   Luke Tierney

 

pr -t -l10 -2 file

paste <(awk 'i=!i' file) <(awk '!(i=!i)' file)

awk '{a[NR]=$0}END{for(i=1;i<=NR;i++) print a[i],a[++i]}' file

 

awk '{a[NR%10]=1}END{for(i=1;i<=NR;i++)print i,NR,a[i],a[i%10]}' file

1 20 1 1

2 20 1 1

3 20 1 1

4 20 1 1

5 20 1 1

6 20 1 1

7 20 1 1

8 20 1 1

9 20 1 1

10 20  1

11 20  1

12 20  1

13 20  1

14 20  1

15 20  1

16 20  1

17 20  1

18 20  1

19 20  1

20 20  1

 

cat file

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

18

19

20

awk '{b=(a[NR%10]=a[NR%10]?a[NR%10]"\t"$0:$0);print b}' file

1

2

3

4

5

6

7

8

9

10

1  11

2  12

3  13

4  14

5  15

6  16

7  17

8  18

9  19

10 20

 

awk '{a[NR%10]=a[NR%10]?a[NR%10]"\t"$0:$0;print a[NR%10]}' file

1

2

3

4

5

6

7

8

9

10

1  11

2  12

3  13

4  14

5  15

6  16

7  17

8  18

9  19

10 20

 

awk '{a[NR%10]=a[NR%10]?3"\t"$0:$0;print a[NR]}' d

1

2

3

4

5

6

7

8

9

 

 

 

 

awk '{a[NR%10]=a[NR%10]?3"\t"$0:$0;print a[1]}' d

1

1

1

1

1

1

1

1

1

1

3  11

3  11

3  11

3  11

3  11

3  11

3  11

3  11

3  11

3  11

 

awk '{a[NR%10]=a[NR%10]?a[NR%10]"\t"$0:$0;print a[2]}' file

 

2

2

2

2

2

2

2

2

2

2

2  12

2  12

2  12

2  12

2  12

2  12

2  12

2  12

2  12


22.

cat file

 

001784 HCART3 ACS 3 - - 15 91488 ACTIVE
001812 HCART3 ACS 3 - - 15 94912 ACTIVE
fwefwrefwerfer
001812 HCART3 ACS 3 - - 15 94912 ACTIVE
fwefwefwe
001812 HCART3 ACS 3 - - 15 94912 ACT

 

统计ACTIVE行出现的次数:

awk '/ACTIVE/{p++}END{print p}'

 

23.

cat file
aaa
bbb
ccc
ddd
eee
fff
ggg
hhh

 

pattern等于ddd时,取其前1行:

awk '!/ddd/{m=$0}/ddd/{print m}' file
awk '!/ddd/{p=NR;a[NR]=$0}/ddd/{print a[p];exit}'

awk '{a[NR]=$0}/eee/{p=NR}END{print a[p-1]}'

 

24.

cat file
1 a
2 b
3 c 

 

close关闭文件

awk '{print NR,$0 > "b.txt";close("b.txt")}' file

3 c

 

每次写入后都关闭文件,那么下次写入时就又重新打开文件
而每次打开又是覆盖的方式,这样file里最后就只剩下最后一行记录

 

25.

有没有将两个输出或者说变量上每列分别合在一起的方法
http://bbs3.chinaunix.net/viewthread.php?tid=1752341

 

$ var1='a
> b
> c
> d'
$ var2='A
> B
> C
> D'
$ export var2
$ echo "$var1" | awk '{"echo \042$var2\042"|getline var2;print $1""var2}'
aA
bB
cC
dD

 

26.

从shell中向awk传入字符串

echo "Stand-by" | awk '{print length($0)}'

 

设置文件名为一变量,管道输出到awk,只返回其扩展名

STR="mydoc.txt"  $ echo $STR|awk 'BEGIN{print substr($STR, 7)}' 

 

27.

http://bbs.chinaunix.net/forum.php?mod=viewthread&tid=4171295&page=1#pid24374435

文本如下:
1       R
        S
        T
2       FF
        GG
        HH
3       KKK
        LLL
        PPP
        OOO

 

想要达到的目的:
1       R
1       S
1       T
2       FF
2       GG
2       HH
3       KKK
3       LLL
3       PPP
3       OOO

 

awk 'NF!=2{$0=s"\t"$1}{s=$1}1' file

……

 

 

awk '{print $1}' f2
1
S
T
2
GG
HH
3
LLL
PPP
OOO

 

awk 'NF!=2{print $1}' f2
S
T
GG
HH
LLL
PPP
OOO


awk 'NF==1{print $1}' f2
S
T
GG
HH
LLL
PPP
OOO

 

awk 'NF>1{print $1}' f2
1
2
3

 

awk 'NF!=2{$0=s"\t"$1}{s=$1;print s}' f2
1
1
1
2
2
2
3
3
3
3

 

awk '{s=$1;print s}NF!=2{$0=s"\t"$1}' f2
1
S
T
2
GG
HH
3
LLL
PPP
OOO

 

awk 'NF!=2{$0=s"\t"$1}{s=$1}1' f2
1       R
1 S
1 T
2       FF
2 GG
2 HH
3       KKK
3 LLL
3 PPP
3 OOO

 

 

awk 'NF!=2{$0=s"\t"$1}1' f2
1       R
 S
 T
2       FF
 GG
 HH
3       KKK
 LLL
 PPP
 OOO

 

awk 'NF==2{s=$1}NF!=2{$0=s"\t"$1}1' f2
1       R
1 S
1 T
2       FF
2 GG
2 HH
3       KKK
3 LLL
3 PPP
3 OOO

 

awk '{s=$1}NF!=2{$0=s"\t"$1}1' f2
1       R
S S
T T
2       FF
GG GG
HH HH
3       KKK
LLL LLL
PPP PPP
OOO OOO

 

28.

http://bbs.chinaunix.net/thread-4171080-1-1.html   awk怎么排除一列输出其他的列

cat file:

1|2|3|4|


怎么排除掉第三列输出
1|2|4|

 

awk -vRS="|" -v ORS="|" '{if(NR!=3)print $0}'

如果没有非空字段的话:
awk -F"|" '{$3="";gsub("[|]+","|",$0)}1' OFS="|"

 

awk -F'|' '{for(i=1;i<NF;i++)if(i!=3)printf $i"|";print ""}' 

 

29.

http://bbs.chinaunix.net/thread-2300359-1-1.html  bash之printf

 

http://bbs.chinaunix.net/thread-4165677-4-1.html  重复打印100次:

printf -- '%.0s-' {1..100};echo
----------------------------------------------------------------------------------------------------

 

 length=100
eval printf -v line '%.0s-' {1..$length}
echo $line

----------------------------------------------------------------------------------------------------

 

awk 'BEGIN{while(i++<100)s=s"-";print s}'
----------------------------------------------------------------------------------------------------

 

seq 100|awk '{printf "-"}'

----------------------------------------------------------------------------------------------------

 

for i in $(seq 20);do echo -n abc;done
for i in `seq 20`;do printf abc;done

----------------------------------------------------------------------------------------------------

 

30.

http://bbs.chinaunix.net/thread-4157887-1-1.html

cat file:

>a1
1
>a1
11
>a1
111
>a2
2
>a2
22
>b1
3
>b1
33

 

将各个title 下边的合在一起 输出如下:
>a1
1
11
111
>a2
2
22
>b1
3
33

 

awk '(/^>/&&!a[$1]++)||/^[^>]/'

awk '/^>/&&!a[$1]++||!/^>/'

awk '{if(/^[>]/){t=$0} else {a[t]=a[t]"\n"$0}}END{for (i in a) print i,a[i]}'

awk '!a[$0]++' 

awk '/>a1/{m++;x=NR}m==1&&NR-x<=1;m>1&&NR-x<=1&&NR-x>0;/>a2/{n++;y=NR}n==1&&NR-y<=1;n>1&&NR-y<=1&&NR-y>0;/>b1/{i++;j=NR}i==1&&NR-j<=1;i>1&&NR-j<=1&&NR-j>0'

 

 

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