Given a list of the integer numbers and we have to print all perfect numbers present in the given list.

This Program iterating through each number one by one in the list, and check whether a given number is a perfect number or not. If a perfect number is found then print it else skip it.

In this program, checkPerfectNum()

checkPerfectNum()函数查找除该数字外的所有正数，然后将其全部求和，然后检查理想的数字条件。

Explanation:

Note:

### (Python code to print perfect numbers from the given list of integers)

``````# Define a function for checking perfect number
# and print that number
def checkPerfectNum(n) :
# initialisation
i = 2;sum = 1;

# iterating till n//2 value
while(i <= n//2 ) :
# if proper divisor then add it.
if (n % i == 0) :
sum += i

# incrementing i by one
i += 1

# check sum equal to n or not
if sum == n :
print(n,end=' ')

# Main code
if __name__ == "__main__" :

# take list of number as an input from user
# and typecast into integer
print("Enter list of integers: ")
list_of_intgers = list(map(int,input().split()))

print("Given list of integers:",list_of_intgers)

print("Perfect numbers present in the list is: ")
# Iteration through the each element of
# the list one by one
for num in list_of_intgers :
# function call
checkPerfectNum(num)``````

Output

``````Enter list of integers:
14 20 6 78 28
Given list of integers: [14, 20, 6, 78, 28]
Perfect numbers present in the list is:
6 28``````