坐标排序是关键
转载 2019-08-04 18:07:00
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求矩形的并 矩形个数 1...20m次询问 回答要求的r个矩形的并容斥原理dfs优化: 遇到面积交为0时 这个dfs分支可以不下去了#include #include #include#include #include #include #include #include using namespace std;//#define LL long long#define LL __int64struct Rectan{ int x1,y1; int x2,y2; Rectan jiao(Rectan &R) { Rectan t; t.x1...
原创 2021-07-29 16:19:52
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Problem Description Given two rectangles and the coordinates of two points on the diagonals of each rectangle,you have to calculate the area of the intersected part of two rectangles. its sides are pa
原创 2022-05-14 11:41:11
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Project Euler 85: Investigating the number of rectangles in a rectangular gridNumber of Rectangles in a GridGiven a grid of size m x n, calculate the ...
转载 2015-07-03 19:21:00
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Rectangle类介绍                               &nbs
Four rectangles are given. Find the smallest enclosing (new) rectangle into which these four may be fitted without overlapping. By smallest rectangle,
转载 2017-04-03 18:55:00
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题意:根据给定的垂直和水平的线段,求能组成的矩形有多少个。题解:因为题
原创 2023-07-18 18:39:26
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【思维】C. Rectangles 传送门 题意:在n个矩形中取n-1个矩形来对其所在的区域取交集,如果最终所形成的区域仍是存在的,就输出这个区域内任意一个点的坐标 思路:提前处理好前i个矩形的交集情况和后i个矩形的交集情况,然后从1到n枚举一个点,把这个点两边的交集情况再做一次合取(取交集),判断 ...
转载 2021-09-17 09:16:00
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Problem DescriptionGiven two rectangles and the coordinates of two points on the diagonals of each rectangle,you have to calculate the area of the intersected part of two rectangles. its sides are p
原创 2023-02-20 10:45:56
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smallest enclosing (new) rectangle into which these four may be fitted without overlapping. B
原创 2023-02-24 10:32:23
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Question:Given two axis-aligned rectangles A and B. Write a function to determine if the two rectangles overlap.http://leetcode.com/2011/05/determine-if-two-rectangles-overlap.html private static
转载 精选 2015-01-19 09:21:54
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题目链接:uva 10574 - Counting Rectangles 题目大意:给出n个点,问选出4个点作为定点,能够组成多少个平行与坐标轴的矩形。 解题思路:首先将点依照x排序(优化),然后处理出全部平行于y轴的线段。记录这些线段的y1和y2,接着仅仅要找出y1和y2值均相等的边,C(2cnt
转载 2016-01-29 11:52:00
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RectanglesTime Limit: 2000MS Memory Limit: 65536KTotal Submissions: 3927 Accepted: 1150DescriptionYou are developing a software for painting rectangles on the s
原创 2022-04-20 09:49:17
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护区间最值和最值的下标 当更新了(n-1)条边和n条边时分别判断一下 当前是否存在一个点被覆盖了至少(n-1)次 有则输出   其实直接搞一个前缀后缀就好 枚举到i时 看i-1之前和i+1之后里最大的x1...
原创 2022-06-16 00:36:04
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题意:给定一些线 判断 一共有多少矩形 和之前那题cf u型 有点类似 枚举 与x轴平行的边 然后扫出与y轴平行的边(与这两条枚举边都相交) 把该边x放入树状数组 求贡献即可 该贡献为 枚举的两条边为矩形的上下底的矩形个数 #include<bits/stdc++.h> using namespac
转载 2019-07-15 16:54:00
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HTML5 Canvas Graphics and Animation/** * Created by Answer1215 on 3/19/2015. */window.onload = function() { //var canvas = $("#canvas")...
转载 2015-03-19 21:34:00
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Packing RectanglesIOI 95 The six basic layouts of four rectangles Four rectangles are given. Find the smallest enclosing (new) rectangle into which these four may be fitted without
转载 2012-07-20 16:48:00
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大模拟题,按要求建立多边形,先定位斜边的位置,再分类讨论~ #include<bits/stdc++.h> using namespace std; const int maxn=1014; struct node { double x,y; }Node[2][maxn]; double dista
转载 2020-02-13 11:32:00
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一、题目 点此看题 二、解法 考虑如果这个问题放在一维上是具有单调性的,尺取法可以做到 \(O(n)\) 我们可以通过枚举上下边界把它变成一维问题,从左往右扫可以做到 \(O(n^3)\) 我们考虑优化掉边界枚举的过程,也就是我们固定上边界,移动下边界。设 \(f_l\) 表示在上下边界中 \(y= ...
转载 2021-10-22 11:07:00
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  #include <bits/stdc++.h> usi...
原创 2022-06-16 06:15:39
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