Given an unsorted array, find the maximum difference between the successive elements in its sorted form.Try to solve it in linear time/space.Return 0 ...
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2014-12-17 22:59:00
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Given an unsorted array, find the maximum difference between the successive elements in its sorted form.Try to solve it in linear time/space.Return 0 ...
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2015-01-16 16:40:00
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Given an unsorted array, find the maximum difference between the successive elements in its sorted form. Return 0 if the array contains less than 2 el
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2016-07-27 11:13:00
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简述GAP本身是一个Profile，并不是Protocol，其作用是定义，BR/EDR可以选择实现GAP Service的
14.3.1 InnoDB Locking InnoDB 锁本章节描述InnoDB 使用的锁类型:Shared and Exclusive LocksIntention LocksRecord LocksGap LocksNext-Key LocksInsert Intention Locks...
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2016-06-07 23:08:00
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环境: OS:Centos 7 DB:11.2.0.4 1.主从切换后发现,新的主库的状态是RESOLVABLE GAPSQL> select switchover_status from v$database; SWITCHOVER_STATUS RESOLVABLE GAP 2.检查下数据库的参 ...
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2021-08-19 15:42:00
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Given an unsorted array, find the maximum difference between the successive elements in its sorted form.Try to solve it in linear time/space.Return 0 ...
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2015-01-26 12:49:00
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Gap HDU - 1067Let’s play a card game called Gap. You have 28 cards labeled with two-digit 1 to 7)...
The Global Fertility GapFar from having too many children, many women in developing countries, like their peers in the rich world, are actually having too few: that is, fewer children than t
DG备库出现ORA-01157 cannot identify/lock data file 201 - see DBWR trace file ，ORA-01110，ORA-01111 ，日志无法应用，switchover_status显示unresolve gap，ORA-01110: data file 63: '/u01/app/oracle/product/11.2.0/db_1/dbs/UNNAMED00063'。。。。
最终恢复备库。
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2015-04-09 15:25:29
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Prime GapTime Limit: 5000MSMemory Limit: 65536KTotal Submissions: 6597Accepted: 3775DescriptionThe sequence of n − 1 consecutive composite numbers (positive integers that are not prime and not equal to 1) lying between two successive prime numbers p and p + n is called a prime gap of length n. For e
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2021-07-29 16:17:50
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Given an unsorted array, find the maximum difference between the successive elements in its sorted form.Try to solve it in linear time/space.Return 0 ...
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2015-07-13 18:08:00
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gap lock没有sx冲突一说,在主键上的查询如何没有对应的记录，也是next-key lock,不是单纯的行锁
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2021-09-07 18:19:41
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Problem DescriptionThe sequence of n 1
桶排序，由于num中的数字肯定在[min,max]区间内，所以根据抽屉原理，假设num中有n个数字，则最大的gap必然要大于dis=(max-min)/(n-1)，所以我们可以把num所在的范围分成等间隔的区间，相邻区间内的元素之间的最大差值，即为要寻找的gap。TODO
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2015-07-09 15:58:00
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原题链接 考察:bfs 思路: 考虑过IDA*,但是搜索层数不一定很浅.然后就是A*,想法是所有不在位置上的数的个数(空白部分不计).但是做之前为了搞懂题意看了讨论区,结果暴雷...看到题解大字标题bfs+hash.....我错了,以后还是自己搞懂题意555 普通的bfs就可以过.可以将数组定义为结
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2021-04-23 13:34:00
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点击打开链接第一次用哈希 感觉和状压就是一回事。。#include <bits/stdc++.h>using namespace std;#define M 1000007struct node{ int t[10][10]; int s;};queue <node> que;int num[10][10],tar[10][10]...
Given an unsorted array, find the maximum difference between the successive elements in its sorted form. Return 0 if the array contains less than 2 el
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2019-09-11 03:03:00
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