//纯计算题,三角形内,已知两点坐标A(x1,y1),B(x2,y2),求第三点的坐标C(x3,y3),其中顶点A,B到C距离都为2//由 (x3-x1)^2+(y3-y1)^2=4 和 (x3-x2)^2+(y3-y2)^2=4 //可得 2(x2-x1)*x3+2(y2-y1)*y3=x2^2-x1^2+y2^2-y1^2 (1)//设A,B距离为L,则顶点C到直线AB的距离 H=2*sin<CAB=2*√(1-L^2/16) //再应用点( x0,y0)到直线ax+by+c=0 的距离公式 |ax0+by0+c|/√(a^2+b^2)//可得 H=| 1/(x2-x1) *x3 -
转载 2011-07-04 18:17:00
58阅读
Two CylindersSpecial Judge Time Limit: 2000/1000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others)Submit Statistic Next ProblemProblem Description      In this problem you
原创 2021-09-04 15:45:15
100阅读
先算出积分表达式:
原创 2023-07-05 19:06:18
56阅读
题目链接:点击打开链接给定r1,r2表示2个圆柱体的半径这两个圆柱体高是正无穷,互相垂直,问相交的最大面积#include #include #include #include #define M 410#define inf 0x3f3f3f3fconst double eps = 1e-8;template inline bool rd(T &ret)
原创 2021-08-13 14:04:39
102阅读
Flow Around Circular Cylinders Volume 1: Fundamentals- zdrakovichNominally Two-Dimensional Cylinder In An Almost Disturbance-Free FlowConceptual overv
原创 2021-07-28 11:38:19
109阅读
suselinux:~ # fdisk -l Disk /dev/sda: 85.8 GB, 85899345920 bytes 255 heads, 63 sectors/track, 10443 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Device Boot Start End
原创 2013-06-18 00:00:39
3123阅读
服务器端: [root@scsi ~]# fdisk -l Disk /dev/sda: 32.2 GB, 32212254720 bytes 255 heads, 63 sectors/track, 3916 cylinders Units = cylinders of 16065 * 512 =
原创 2021-08-07 11:24:21
666阅读
Oracle ASM for linx as 4 x86- 创建过程1、划分区 Disk /dev/sdb: 5368 MB, 5368709120 bytes 255 heads, 63 sectors/track, 652 cylinders Units = cylinders of 16...
转载 2010-01-06 12:03:00
185阅读
2评论
root@chenzhijun-lnx:/etc# fdisk -l Disk /dev/sda: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/ph
原创 2011-06-24 16:26:18
531阅读
1. 添加了磁盘后查看,没有刷新出来 [root@node /]# fdisk -l Disk /dev/sda: 17.2 GB, 17179869184 bytes 255 heads, 63 sectors/track, 2088 cylinders Units = cylinders of
转载 2020-04-01 11:35:00
143阅读
  一、sfdisk -l   [root@localhost ~]# sfdisk -l   Disk /dev/sda: 4863 cylinders, 255 heads, 63 sectors/track   Units = cylinders of 8225280 bytes, blocks of 1024 bytes, counting from 0   Device Boot
转载 2011-11-30 17:47:08
348阅读
bj-207:~ # fdisk -l Disk /dev/sda: 299.4 GB, 299439751168 bytes 255 heads, 63 sectors/track, 36404 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes    Device Boot  &n
转载 精选 2012-08-08 00:42:03
2209阅读
创建、管理LVM: 创建分区 Disk /dev/xvdc: 2147 MB, 2147483648 bytes 255 heads, 63 sectors/track, 261 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 byt
原创 2014-08-24 18:03:57
444阅读
查看新增的磁盘[root@FTPAP ~]# fdisk -l Disk /dev/sdb: 536.9 GB, 536870912000 bytes 255 heads, 63 sectors/track, 65270 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical
第一、检查硬盘设备是否有数据盘 # 先执行 fdisk -l # 以下是执行结果 Disk /dev/vda: 21.5 GB, 21474836480 bytes 255 heads, 63 sectors/track, 2610 cylinders Units = cylinders of 16 ...
转载 2021-08-06 10:17:00
606阅读
2评论
#fdisk -l /dev/sda Disk /dev/sda: 320.0 GB, 320072933376 bytes 255 heads, 63 sectors/track, 38913 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Device Boot Start End Blocks Id Sys
  fdisk &ndash;l 查看磁盘 Disk /dev/sda: 21.4 GB, 21474836480 bytes 255 heads, 63 sectors/track, 2610 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes    Device Boot&nbs
原创 2013-01-04 23:33:07
493阅读
一、Linux磁盘分区UUID的获取方法 1、# fdisk -l Disk /dev/sda: 1000.2 GB, 1000204886016 bytes 240 heads, 63 sectors/track, 129201 cylinders Units = cylinders of 15120 * 512 = 7741440 bytes Sector size (logic
原创 2011-11-23 11:21:46
6458阅读
[root@rhel5 ~]# fdisk -l  Disk /dev/sda: 68.7 GB, 68719476736 bytes 255 heads, 63 sectors/track, 8354 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes    Device Bo
原创 2014-06-23 13:05:00
591阅读
# fdisk -l Disk /dev/hda: 160.0 GB, 160041885696 bytes 255 heads, 63 sectors/track, 19457 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes (7M多每个柱面) Device Boot Start End
  • 1
  • 2
  • 3
  • 4
  • 5